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Masteriza [31]
3 years ago
10

A landscaper working at a constant rate can lay 3 squares of sod in 5 minutes. Working at this rate, how many squares of sod can

he lay in 2 hours?
Mathematics
1 answer:
Murljashka [212]3 years ago
7 0
They can lay 72 squares of sod in 2 hours.
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Simplify this equation<br> (3X^2+21X+33)/(X+5)
Amiraneli [1.4K]

Answer:

(3x^2+21x+33) / (x+5)

You can use long division:

(3x^2+21x+33)

--------------------

       (x+5)

=3x+6+ 3/x+5

Step-by-step explanation:

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PLS HELP! Which transformation could take figure P to figure Q?
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Answer:

3. A single translation

Step-by-step explanation:

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Show that the following statement is an identity by transforming the left side into the right side. sin θ (sec θ + csc θ) = tan
ExtremeBDS [4]

Answer:

Step-by-step explanation:

Required to prove that:

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Steps:

Recall sec θ= 1/cos θ and cosec θ=1/sin θ

Substitution into the Left Hand Side gives:

Sin θ(Sec θ + Cosec θ)

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Expanding the Brackets

=sinθ/cos θ + sinθ/sinθ

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The book Kathy is reading is 540 pages long. So far, she has read 405 pages. What percent of the book does she have left to read
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Given the information below, write the conclusion in context. 1. H0 : The proportion of defective batteries = 0.02 2. HA : The p
Marizza181 [45]

Answer:

z = -1.23

And we can calculate the p value with the following probability taking in count the alternative hypothesis:

p_v = P(z

And for this case using a significance level of \alpha=0.05 ,0.1 we see that the p value is larger than the significance level so then we can conclude that we FAIL to reject the null hypothesis and we don't have enough  evidence to conclude that the true proportion is less than 0.02

Step-by-step explanation:

For this case we want to test the following system of hypothesis:

Null hypothesis: p =0.02

Alternative hypothesis: p < 0.02

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

And for this case we know that the statistic is given by:

z = -1.23

And we can calculate the p value with the following probability taking in count the alternative hypothesis:

p_v = P(z

And for this case using a significance level of \alpha=0.05 ,0.1 we see that the p value is larger than the significance level so then we can conclude that we FAIL to reject the null hypothesis and we don't have enough  evidence to conclude that the true proportion is less than 0.02

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3 years ago
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