PLEASE HELP I'M STUCK ;-;

Mathematics

2 answers:

Tems11 [23]2 years ago

6 0

-4.2-6y+3.6........whaja

QveST [7]2 years ago

5 0

Answer:

the distributive property is supposed to simplify your equation

Step-by-step explanation:

-4.2 - 6y + 3.6

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2 years ago

Which of the following is equivalent to tan 5pie/6?

nataly862011 [7]

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5 0

2 years ago

The length of a rectangle is 5 more than twice the width. the perimeter is 130. what is the area?

vekshin1

L the length W the width

The length of a rectangle is 5 more than twice the width
L = 5+ 2W

the perimeter is equal the sum of sides =130

L+L+W+W =130

by subtitution we replace L by L = 5+ 2W

5+ 2W+5+ 2W +W+W = 130

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7 0

2 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

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Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: rational equation fraction solution algebra

7 0

2 years ago