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Masteriza [31]
3 years ago
13

Does doubling the height of the cylinder has the same affect on the volume of a cylinder as doubling the radius explain

Mathematics
1 answer:
musickatia [10]3 years ago
3 0
Volume of cylinder = π.R².h , where R = radius and h = height

Let's replace h by 2h:
V₁= πR².(2h) → V₁ = 2π.R².h

Now let's double R, the radius (and keep h as h)
V₂ = π.(2R)².h → V₂ = 4.π.R².h

Compare V₁ to V₂→ (V₁ = 2π.R².h  and  V₂ = 4.π.R².h).
It's obvious that V₂ = 2.V₁

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2 years ago
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At the neighborhood grocery, 4.5 pounds of chicken breast cost $53.28. Benjamin
otez555 [7]
If my math is correct this should be a simple equation. First you’d start off by figuring out how much money chicken costs per one pound.
53.28 / 4.5 = $11.84 per pound
Now take how much money the chicken costs per pound and divide it by how much Benjamin spent.
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3 years ago
The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

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