Answer:
![G(T(x)) = 27(x + 6.9)](https://tex.z-dn.net/?f=G%28T%28x%29%29%20%3D%2027%28x%20%2B%206.9%29)
Step-by-step explanation:
Given
![T(x) = 9(x + 6.9)](https://tex.z-dn.net/?f=T%28x%29%20%3D%209%28x%20%2B%206.9%29)
![G(x) = 3x](https://tex.z-dn.net/?f=G%28x%29%20%3D%203x)
Required [Missing from the question]
G(T(x))
We have:
![G(x) = 3x](https://tex.z-dn.net/?f=G%28x%29%20%3D%203x)
This implies that:
![G(T(x)) = 3(T(x))](https://tex.z-dn.net/?f=G%28T%28x%29%29%20%3D%203%28T%28x%29%29)
Substitute: ![T(x) = 9(x + 6.9)](https://tex.z-dn.net/?f=T%28x%29%20%3D%209%28x%20%2B%206.9%29)
![G(T(x)) = 3[9(x + 6.9)]](https://tex.z-dn.net/?f=G%28T%28x%29%29%20%3D%203%5B9%28x%20%2B%206.9%29%5D)
Open bracket
![G(T(x)) = 27(x + 6.9)](https://tex.z-dn.net/?f=G%28T%28x%29%29%20%3D%2027%28x%20%2B%206.9%29)
Answer is a look at y and it is the only answer that makes sense due to increase exponentionally in y while X is in 3a
You need 5 more gallons for a full tank.
Since it takes 10 gallons to increase the gauge from 1/4 to 3/4 (change of 2/4 which is the same as 1/2), it must have taken 10 gallons to fill up to halfway for the tank.
Thus the full amount would be 10*2 = 20 gallons
However, since there is already 3/4 gasoline in the tank, we only need an extra 1/4 of 20 for it to be full.
So, 20*1/4 = 5
We need to add 5 gallons for a full tank.
Answer:
P(A' ∩ B) = 0.12
Step-by-step explanation:
Given:
P(A) = 0.41, P(B) = 0.32 and P(B' ∩ A) = 0.21
To Find:
P(A' ∩ B)
Solution:
Since, P(B' ∩ A) = P(A) - P(A ∩ B)
By substituting the values given,
0.21 = 0.41 - P(A ∩ B)
P(A ∩ B) = 0.41 - 0.21
= 0.20
Since, P(A' ∩ B) = P(B) - P(A ∩ B)
P(A' ∩ B) = 0.32 - 0.20
= 0.12
Therefore, P(A' ∩ B) = 0.12 is the answer.