Question

Penelope and george go trick or treating. Penelope gets 152 pieces of candy. George gets 124 pieces of candy. Penelope eats 5 peices of candy a day. George eats 4 pieces of candy a day. After how many days will georde have the same anount of candy as penelope?

Answer 1

Answer:

In 28 days George have the same amount of candy as Penelope.

Step-by-step explanation:

Given:

Penelope has 152 pieces of candy.

George has 124 pieces of candy.

Penelope eats 5 pieces each day.

George eats 4 pieces each day.

To find in how many days will George have the same amount of candy as Penelope.

Solution:

Let the number of days in which George have the same amount of candy as Penelope be = $x$

Using unitary method.

If Penelope eat 5 pieces of candy in 1 day.

In $x$ days, he will eat = $5x$ candies

Thus, after $x$ days number of candies left with Penelope = $152-5x$

If George eat 4 pieces of candy in 1 day.

In $x$ days, he will eat = $4x$ candies

Thus, after $x$ days number of candies left with George = $124-4x$

Since, in $x$ days George have the same amount of candy as Penelope, so we have:

$124-4x=152-5x$

Solving for $x$

Adding $5x$ both sides.

$124-4x+5x=152-5x+5x$

$124+x=152$

Subtracting 124 both sides.

$124-124+x=152-124$

∴ $x=28$

Thus, in 28 days George have the same amount of candy as Penelope.