Successor of -501 is
1 answer:
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Answer:
a) P (0 defective component) = 0.5
P( 1 defective component ) = 0.35
P( 2 defective component ) = 0.15
b) P( 0 ) = 0
p ( 1 ) = 1
p ( 2 ) = 0.33
Step-by-step explanation:
p( no defective ) = 0.5
p( 1 is defective ) = 0.35
p( 2 is defective ) = 0.15
Given that 2 components are selected at random
<u>a) Given that neither component is defective </u>
Probability of 0 defective component = 0.5
P( 1 defective component ) = 0.35
P( 2 defective component ) = 0.15
<u>b) Given that one of the two tested component is defective </u>
P( 0 defective ) = 0
P( 1 defective ) = P ( ) = p( x = 1 ) / 1 - P ( x = 0 )
= ( 0.5 )^1 ( 0.5 )^0 / 1 - ( 0.5)^0 (0.5)^1
= 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 = 1
p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )
= ( 0.5 )^2 ( 0.5 )^0 / 1 - ( 0.5)^0 (0.5)^2
= 0.25 / 0.75 = 0.33
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Given:
The figure of two parallel lines MP and QS.
A transversal line KL interests the two parallel lines.
To find:
The .
Solution:
If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.
In the given figure and
corresponding angles. It means their measures are equal.
Therefore, .