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algol [13]
3 years ago
12

Solve the equation of e^x-2=(1/e^6)^x+3.

Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Answer:

x = -16/7

Step-by-step explanation:

The equation as written reduces to finding the solution to a 7th-degree polynomial. The one real solution, found using a graphing calculator, is ...

x ≈ 1.60945071137

_____

Since this is beyond the scope of most algebra courses, we suspect you want the solution to ...

e^(x-2) = (1/e^6)^(x+3)

x -2 = -6(x +3) . . . . . . . . take the natural log of both sides

x -2 = -6x -18 . . . . . . . . . eliminate parentheses

7x -2 = -18 . . . . . . . . . . . add 6x

7x = -16 . . . . . . . . . . . . . add 2

x = -16/7

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Answer:

\displaystyle \text{d. }y=\frac{-6}{x}

Step-by-step explanation:

If two values x and y are inversely proportional, their product is <em>always</em> some maintained constant (the product of x and y is always maintained). This way, if one goes up, the other must go down by the same extent. By definition, this represents an inversely proportional relationship.

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The constant -6 must be maintained as the product of x and y for all values of x and y for them to be inversely proportional. Thus, we have the equation:

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Divide both sides by x to isolate y:

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