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3 years ago

Factor the difference of two perfect squares using the X method. What are the two binomial factors for x2 – 25?

Mathematics

2 answers:

Daniel [21]3 years ago

8 0

Answer:

its D

Step-by-step explanation:

lilavasa [31]3 years ago

4 0

That is D
positive sign in one bracket and negative in the other

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PLEASE HELP ME I WILL MARK YOU BRAINLIEST FOR THIS ANY ANSWERS!!!)Mr. Perez designs a probability model to help him predict whic

Nesterboy [21]

Answer:

Number A. is True. B. is False. C. is IDK D. is False. E. is true.

Step-by-step explanation:

If you read it you can tell plus I broke it down and solved it on paper.

6 0

3 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Please help me with this!

morpeh [17]

Answer:

Step-by-step explan

6 0

2 years ago

Help this is due tomorrow

Helen [10]

-4.4(s - 2) + 6.9s = 14.8

Distribute -4.4 into the parenthesis:

-4.4s + 8.8 + 6.9s = 14.8

Combine like terms:
2.5s + 8.8 = 14.8

Subtract 8.8 from both sides of the equation:

2.5s + 8.8 - 8.8 = 14.8 - 8.8

2.5s = 6

Divide both sides by 2.5:

2.5s/2.5 = 6/2,5

s = 2.4

s =

6 0

3 years ago

PLS HELP!!!!!!!!!!!!!

fgiga [73]

Answer:

7+1- -7

Step-by-step explanation:

i just guessed :)

3 0

3 years ago