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UNO [17]
3 years ago
7

Please help me with this!

Mathematics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

Step-by-step explan

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a-plus auto body is painting desings on a customer's car. they had 18 pints of blue paint on hand. they used 1/2 of it for the f
netineya [11]

4³/₄ pints

<h3>Further explanation</h3>

<u>Given:</u>

A-Plus auto body is painting desigs on a customer's car.

  • They had 18 pints of blue paint on hand.
  • They used \frac{1}{2} of it for the flames, and \frac{1}{3} of it for the sparks.
  • They needed 7\frac{3}{4} pints of blue paint to paint the next design.

<u>Question:</u>

How many more pints of blue paint will they need?

<u>The Process:</u>

From the denominators 2 and 3 above, we get LCM = 6.

Let us draw a diagram that contains all the pints.

18 \ pints \div 6 \ units = 3 \rightarrow \boxed{3}\boxed{3}\boxed{3}\boxed{3}\boxed{3}\boxed{3} = 18 \ pints

The flames: \frac{1}{2} or half of 6 unit above, that is \boxed{3}\boxed{3}\boxed{3} = 9 \ pints

The sparks: \frac{1}{3} = \frac{2}{6} or 2 of 6 unit above, that is \boxed{3}\boxed{3} = 6 \ pints

So, the remainder is 18 - 9 - 6 = 3 pints.

They needed 7\frac{3}{4} pints of blue paint to paint the next design.

Let us count how many more pints of blue paint will they need.

\boxed{7\frac{3}{4} - 3 = ?}

\boxed{= \bigg( 7 + \frac{3}{4} \bigg) - 3}

\boxed{= 7 - 3 + \frac{3}{4}}

\boxed{\boxed{ \ 4\frac{3}{4}}}

Thus, they 4\frac{3}{4} pints more of blue paint.

<h3>Learn more</h3>
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  2. How many students are in each class brainly.com/question/12251555
  3. How many students are in the grade brainly.com/question/1070972  

Keywords: A-Plus, auto body, painting, designs, on a customer's car, they had 18 pints, blue paint, 1/2, for the flames, 1/3, the sparks, they needed, 7³/₄, the next design, how many more, will they need

3 0
4 years ago
If Victoria's rent is $400 per month, and she pays an additional $150 for utilities and $35 for advertising each month, what is
USPshnik [31]

Answer:

C(n) = 435n + 150

Step-by-step explanation:

Given

Base = 400 -- Base charge per month

Utilities = 150

Adverts = 35 per month

Required

The cost function

To do this, we multiply the rates by the number of months.

So, we have:

C(n) = Base * n + Adverts * n + Utilities

So, we have:

C(n) = 400 * n + 35 * n + 150

C(n) = 400n + 35n + 150

C(n) = 435n + 150

3 0
3 years ago
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