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3 years ago

-2-5(4n-6)=-132 not really sure how to do this one ..

Mathematics

2 answers:

uranmaximum [27]3 years ago

8 0

All you have to do is follow PEMDAS (if you don't know what that is, search it up).

-2-5(4n-6)=-132

Distribute the 5 to everything in the parentheses.

-2-20n+30= -132

Combine like terms.

-20n+28 = -132

Subtract 28 from both sides.

-20n = -160

Divide by -20 on both sides.

n = 8

Nikolay [14]3 years ago

8 0

Use order of operations rules to evaluate all terms of -2-5(4n-6)=-132, and then solve for n:

Must multiply -5(4n-6) first: -20n + 30. Then we have -2 - 20n + 30 = -132.

Adding 2 to both sides, we get -20n + 30 = -130, or -20n = -160.

Solving for n, n = 160/20 = 8 = n

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Determine the solution to the system of equations given below y=x^2-5x+15

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Answer:

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Step-by-step explanation:

Use the quadratic formula with the following values.

a = 1

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Substitute and simplify.

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What is the volume of this complex figure

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The volume of the given figure is 210 cubic in..

We need to find the volume of the given figure.

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Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

Divide the given figure into two convenient cuboids. That is one with dimensions length=4 in., breadth=2 in. and height=3 in. Another with length=4 in., breadth=4 in. and height=12 in.

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

Formula:

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3 years ago

PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all

Xelga [282]

Answer:

1. $(A,B) = (3,-2)$

2. The values of t are: -3, -1

Step-by-step explanation:

Given

$\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

$|t| = 2t + 3$

Required

Solve for the unknown

Solving $\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

Take LCM

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}$

Expand the denominator

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}$

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}$

Both denominators are equal; So, they can cancel out

$x + 7 = A(x+1) + B(x-2)$

Expand the expression on the right hand side

$x + 7 = Ax + A + Bx - 2B$

Collect and Group Like Terms

$x + 7 = (Ax + Bx) + (A - 2B)$

$x + 7 = (A + B)x + (A - 2B)$

By Direct comparison of the left hand side with the right hand side

$(A + B)x = x$

$A - 2B = 7$

Divide both sides by x in $(A + B)x = x$

$A + B = 1$

Make A the subject of formula

$A = 1 - B$

Substitute 1 - B for A in $A - 2B = 7$

$1 - B - 2B = 7$

$1 - 3B = 7$

Subtract 1 from both sides

$1 - 1 - 3B = 7 - 1$

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Divide both sides by -3

$B = -2$

Substitute -2 for B in $A = 1 - B$

$A = 1 - (-2)$

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Hence;

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Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

$t = 2t + 3$ and $-t = 2t + 3$

Solving $t = 2t + 3$

Make t the subject of formula

$t - 2t = 3$

$-t = 3$

Multiply both sides by -1

$t = -3$

Solving $-t = 2t + 3$

Make t the subject of formula

$-t - 2t = 3$

$-3t = 3$

Divide both sides by -3

$t = -1$

<em>Hence, the values of t are: -3, -1</em>

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3 years ago

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