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dexar [7]
3 years ago
9

B - (- 7) =-1 what is b?

Mathematics
2 answers:
vivado [14]3 years ago
8 0
Negative times a negative makes a positive
so we can get
B + 7 = -1
then subtract 7 from both sides
B = -1 - 7 = -8

therefore B = -8
irina1246 [14]3 years ago
4 0

B-(-7)= -1

First negative multiply by negative is POSITIVE.

So: B+7= -1

Subtract 7 from both sides

B= -7-1

B= -8.

Answer: -8.

To Check Answer: Plug in the variable of B in the original equation.

So: -8-(-7)= -1

-8+7= -1

-1= -1

If the Solution works out the answer is right.

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2/3 : 1 in its simplest form
slamgirl [31]

Answer:

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Step-by-step explanation:

You need to show the ratio using the smallest whole numbers possible.

Multiply both numbers by 3.

2/3 : 1

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2 : 3

5 0
2 years ago
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

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So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
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frosja888 [35]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Firlakuza [10]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Firlakuza [10]

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Step-by-step explanation:

4 0
3 years ago
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