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Nuetrik [128]
3 years ago
5

Graph f(x)=−0.25x+4.

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0
Here is the graph. (I got it from desmos.com...its a good graphing site) I hope this helps love! :)

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Can someone help me please and show work thank you
VladimirAG [237]

Answer:

60% decrease

Step-by-step explanation:

To work out percentage change you takeaway the original number by the new number (New number-Original number) in this case 24-60=(-36), then divide the decreased amount by the original number and multiply the answer by 100 (Decrease amount ÷ Original number x 100) for this question you'd do (-36)÷60=(-0.6) then (-0.6)x100=(-60).

The minus shows its a decrease in percentage by 60%

(I hope this helps srry if it doesn't make sense)

6 0
3 years ago
9.48 as a mixed number in simplist form
mafiozo [28]

Answer:

<h2>9 12/25.</h2>

Step-by-step explanation:

9.48 as a mixed number in simplest form:

<em><u>948/100</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25= 9 12/25</u></em>

<u>9 12/25 is the mixed number.</u>

8 0
3 years ago
A body builder consumed 5,600 calories yesterday. Today, he consumed 4,200 calories.
hammer [34]

well, the difference from 5600 to 4200 is 1400.

If we take 5600 to be the 100%, how much is 1400 off of it in percentage?

\begin{array}{ccll} amount&\%\\ \cline{1-2} 5600&100\\ 1400&x \end{array}\implies \cfrac{5600}{1400}=\cfrac{100}{x}\implies 4=\cfrac{100}{x} \\\\\\ 4x=100\implies x=\cfrac{100}{4}\implies x=25

5 0
2 years ago
For what value of k does the graph of y = x²-3x-k pass through the point (-1,2)?
gavmur [86]
The value of k should be 2.
 if you plug the y value of the point in the equation for y and do the same with x you should be able to get this answer after fallowing the order of operation.
5 0
3 years ago
A statement Sn about the positive integers is given. Write statements Sk and Sk+1, simplifying Sk+1 completely. Show your work.
pentagon [3]

\displaystyle S_k = \sum\limits_{i=1}^k{i(i+1)} = \dfrac{k(k+1)(k+2)}{3} \\ \\ S_{k+1} = \sum\limits_{i=1}^{k+1}{i(i+1)} = \dfrac{(k+1)(k+1+1)(k+1+2)}{3}=\\ \\ = \dfrac{(k+1)(k+2)(k+3)}{3}

4 0
3 years ago
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