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mixas84 [53]
3 years ago
6

Madison represented the sentence “The product of 3 and the difference of Negative 4 and the quotient of a number and Negative 2

is at most 5” by using the inequality 3 (Negative 4 minus StartFraction n over negative 2 EndFraction) less-than 5.
Which best describes Madison’s error?
“The difference of –4 and the quotient of a number and –2” should be written as StartFraction negative 4 minus n over negative 2 EndFraction.
“The product of 3 and the difference of –4 and the quotient of a number and –2” should be written as 3 (negative 4) minus (StartFraction n over negative 2 EndFraction).
The less than symbol should be replaced with the less than or equal to symbol.
The less than symbol should be replaced with the greater than symbol.
Mathematics
2 answers:
julia-pushkina [17]3 years ago
7 0

9514 1404 393

Answer:

  (c)  The less than symbol should be replaced with the less than or equal to symbol.

Step-by-step explanation:

"At most" means "less than or equal to". Madison needs to use ≤ instead of <.

PilotLPTM [1.2K]3 years ago
5 0

Answer:

C     Its right, dont read the explanation doe.

Step-by-step explanation:

Bingus Chungus Orb

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Step-by-step explanation:

Intersection of the 2 parts of the function is (0,0):

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Answer B

7 0
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Which of the following are true statements using the Associative Property of Multiplication?
dangina [55]

Answer:

All of the following statements are true because the products, three or four numbers, remain the same regardless of how the numbers are grouped.

3 0
3 years ago
Read 2 more answers
If u-ai + bj and v-ci + dj are vectors, then which of the following statements is not true?
alukav5142 [94]

Answer:

Option C

Step-by-step explanation:

Given that u-ai + bj and v-ci + dj are vectors

We have dot product

u.v = (ai+bj).(ci+dj) hence inner product of u and v.  So option a is true

The dot product of u and v is a scalar is true because dot product is always a scalar

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True because we multiply corresponding i components and j components and add.

So only C is not true.

7 0
3 years ago
A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.
iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- |E\ n\ B|

- |B|

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

B = \{6\}

E = \{2,4,6\}

Calculating the size of |E n B|

|E n B| = \{2,4,6\}\ n\ \{6\}

|E n B| = \{2,4,6\}

<em>The size = 3 because it contains 3 possible outcomes</em>

Calculating the size of |B|

B = \{6\}

<em>The size = 1 because it contains 1 possible outcome</em>

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3 years ago
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uranmaximum [27]

Answer:

A. thats the answer

Step-by-step explanation:

carry on learning

4 0
2 years ago
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