Answer:
I don't know sorry it even very hard and diffult for a high school kid
9514 1404 393
Answer:
(a) (4, 8)
Step-by-step explanation:
Apply the transformation rule to the coordinates of point H.
(x, y) → (x +8, y +5)
H(-4, 3) → H'(-4 +8, 3 +5) = H'(4, 8)
Answer:

Step-by-step explanation:
The Universal Set, n(U)=2092


Let the number who take all three subjects, 
Note that in the Venn Diagram, we have subtracted
from each of the intersection of two sets.
The next step is to determine the number of students who study only each of the courses.
![n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x](https://tex.z-dn.net/?f=n%28S%5C%3Aonly%29%3D1232-%5B103-x%2Bx%2B23-x%5D%3D1106%2Bx%5C%5Cn%28F%5C%3A%20only%29%3D879-%5B103-x%2Bx%2B14-x%5D%3D762%2Bx%5C%5Cn%28R%5C%3Aonly%29%3D114-%5B23-x%2Bx%2B14-x%5D%3D77%2Bx)
These values are substituted in the second Venn diagram
Adding up all the values
2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]
2092=2085+x
x=2092-2085
x=7
The number of students who have taken courses in all three subjects, 
Answer:
Sequence 1
Step-by-step explanation:
<u>You need to find the difference between term - the nth term.</u>
<u>The difference / nth term has to to -1/2 (-0.5)</u>
Sequence 1:
-6 * -0.5 = 3 * -0.5 = -3/2 (-1.5) * -0.5 = 3/4 (0.75) * -0.5 = -3/8 (-0.375)
Sequence 2:
4 * -2 = -8 *-2 = 16 * -2 = - 32 * -2 = 64
Sequence 3:
-1/3 ÷ 2 = -1/6 ÷ 2 = 12 ÷ 2 = 24 ÷ 2 = 48
Sequence 4:
400 ÷ -2 = -200 ÷ -2 = 100 ÷ -2 = -50 ÷ -2 = 25
The only sequence with a common ratio of -1/2 is Sequence 1.
Hello!
You use the Pythagorean theorem to solve this

Put in the values it tells you to

Square the numbers

Subtract 19.36 from both sides

Take the square root of both sides
a = 3.3
The answer is 3.3
Hope this helps!