Given :
A = <span>70 years old
H = 172 cm
W = 55 kg
so calculate the the basal energy rate B
B = </span><span>655.096 + 9.563W +1.85H - 4.676A
</span><span>where B is the basal energy rate (in calories), W is the weight (in kilograms), H is the height (in centimeters), and A is the age (in years)
substitute the given
B = </span>655.096 + 9.563(55) +1.85(172) - 4.676(70)
B = 1171.941 cal is the basal energy rate, since he is prescribed for 1000 cal per day is not enough because basal energy is the calorie needed at rest only how about the calorie needed for the daily acivities.
Answer:
c=sqrt21
Step-by-step explanation:
angle c is the angle between a and b, so use the cos law
c^2=a^2+b^2-2*a*b*cosC
c^2= 16+25-2*4*5*1/2
c^2=21
c=sqrt21
Answer:
if you want it in standard form it would be −1/4x-1/2x-5/6
If you want it simplified it would be -3x/4-5/6
Step-by-step explanation:
(This is the best you'll get for 5 points)
Answer:
300 calories
Step-by-step explanation:
he burns 12 calories each lap so you need to know how many laps he ran
which means you need to find the circumference of the track, whose formula is 2πr; remember, radius is half the diameter.
C = 2π75
C = 150π
C ≈ 471
Now divide the total number of feet he ran (11,775) by the circumference to arrive at the number of laps.
11775 ÷ 471 = 25 laps
25 x 12 = 300 calories burned in total