Points a b and c ate noncollinear so therefore they are noncoplanar

Mathematics

1 answer:

Kamila [148]3 years ago

7 0

The answer to your question is skew lines

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What is the distance rounded to the nearest tenth between the points(-5, 3) and (1, -1)?

kakasveta [241]

7.2 units is the distance between the two points (-5,3) and (1, -1).

The formula used for determining the distance between two points is shown below. In case this equation is used for finding the distance between the origin and a point, the value of x1 and y1 would just be equal to zero.

distance = $\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }$

The given points can be directly substituted for the formula.

Let: x2= 1, x1= -5, y2= -1, and y1= 3

distance = $\sqrt{[1-(-5)]^{2} + (-1 -3)^2 }$

distance = $\sqrt{(6)^2+(-4)^2}$

distance = $\sqrt{52}$ or 7.21 units

When rounded to the nearest tenth, the distance between the two points would be 7.2 units.

For more information regarding the distance between points, please refer to the link brainly.com/question/23848540.

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3 0

2 years ago

4\sqrt(3)-3\sqrt(12)+2\sqrt(75)

postnew [5]

Answer:

8√3 Decimal Form: 13.85640646

Step-by-step explanation:

5 0

3 years ago

Please I need this question fast

Mrrafil [7]

We have a linear function $\displaystyle\bf y=\underbrace{k}_{gradient}x+b$ and we know that $\displaystyle\bf \left \{ {{-2\cdot-3+b=2} \atop {-4\cdot -2+b=k}} \right. => \left \{ {{b=-4} \atop {b+8=k} \right. => k=8-4=4 \\\\Answer: \boxed{B) \quad k=4}$