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lesya [120]
3 years ago
10

PLEASE HELP ME I CANT What is the shape of the cross section of the figure that is perpendicular to the rectangular base and pas

ses through the top vertex of the figure?
A) a parallelogram that is not a rectangle.
B)a rectangle
C)a triangle that must have the same dimensions as one of the faces.
D)a triangle that does not have the same dimensions as one of the faces

Mathematics
2 answers:
nadezda [96]3 years ago
8 0

Answer:

D)a triangle that does not have the same dimensions as one of the faces

Step-by-step explanation:

The shape of the cross section, which is perpendicular to the base, has a base of the same length as the base of the pyramid. from the base, two lines go up and inward from the edges, towards the vertex of the pyramid. This makes the shape of a triangle. Since the triangle can be considered the straight edge of a right angle triangle, and the sides of the pyramids would be considered the hypotenuse, the cross section does not have the same dimensions as one of the faces.

SVEN [57.7K]3 years ago
4 0
The answer is D my good sir
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Answer:

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2 years ago
Solve for b A= \frac{a+b}{2}
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A = (a+b)/2
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20 points!!
ANEK [815]

See below for the proof of the equation \frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)

<h3>How to prove the equation?</h3>

The equation is given as:

\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)

Take the LCM

\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)

Expand

\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)

Evaluate the like terms

\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)

Rewrite as:

\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)

Factorize the numerator

\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)

Divide

2(a - b)= 2(a - b)

Both sides are equal

Hence, the equation \frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b) has been proved

Read more about equations at:

brainly.com/question/2972832

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Step-by-step explanation:

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