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lesya [120]
4 years ago
10

PLEASE HELP ME I CANT What is the shape of the cross section of the figure that is perpendicular to the rectangular base and pas

ses through the top vertex of the figure?
A) a parallelogram that is not a rectangle.
B)a rectangle
C)a triangle that must have the same dimensions as one of the faces.
D)a triangle that does not have the same dimensions as one of the faces

Mathematics
2 answers:
nadezda [96]4 years ago
8 0

Answer:

D)a triangle that does not have the same dimensions as one of the faces

Step-by-step explanation:

The shape of the cross section, which is perpendicular to the base, has a base of the same length as the base of the pyramid. from the base, two lines go up and inward from the edges, towards the vertex of the pyramid. This makes the shape of a triangle. Since the triangle can be considered the straight edge of a right angle triangle, and the sides of the pyramids would be considered the hypotenuse, the cross section does not have the same dimensions as one of the faces.

SVEN [57.7K]4 years ago
4 0
The answer is D my good sir
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Given these what is X if B-X=A
ser-zykov [4K]

Answer:

B

Step-by-step explanation:

B-X=A

or

B-A=X

or

X=B-A

X=\left[\begin{array}{ccc}-5&-1&6\\4&1&2\\0&-3&2\end{array}\right] -\left[\begin{array}{ccc}-1&-2&3\\4&8&-6\\0&1&5\end{array}\right] \\=\left[\begin{array}{ccc}-5+1&-1+2&6-3\\4-4&1-8&2+6\\0-0&-3-1&2-5\end{array}\right] \\=\left[\begin{array}{ccc}-4&1&3\\0&-7&8\\0&-4&-3\end{array}\right]

3 0
4 years ago
I know you’re supposed to change the bounds and break up the integral, but for some reason, I can’t get the 44/3. Can someone ex
tatyana61 [14]

First, look for the zeroes of the integrand in the interval [0, 6] :

x² - 6x + 8 = (x - 4) (x - 2) = 0   ⇒   x = 2   and   x = 4

Next, split up [0, 6] into sub-intervals starting at the zeroes we found. Then check the sign of x² - 6x + 8 for some test points in each sub-interval.

• For x in (0, 2), take x = 1. Then

x² - 6x + 8 = 1² - 6•1 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

• For x in (2, 4), take x = 3. Then

x² - 6x + 8 = 3² - 6•3 + 8 = -1 < 0

so x² - 6x + 8 < 0 over this sub-interval.

• For x in (4, 6), take x = 5. Then

x² - 6x + 8 = 5² - 6•5 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

Next, recall the definition of absolute value:

|x| = \begin{cases}x & \text{for }x \ge0 \\ -x & \text{for }x < 0\end{cases}

Then from our previous analysis, this definition tells us that

|x^2 - 6x + 8| = \begin{cases}x^2 - 6x + 8 & \text{for }0

So, in the integral, we have

\displaystyle \int_0^6 |x^2-6x+8| \, dx = \left\{\int_0^2 - \int_2^4 + \int_4^6\right\} (x^2 - 6x + 8) \, dx

Then

\displaystyle \int_0^2 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_0^2 = \frac{20}3 - 0 = \frac{20}3

\displaystyle \int_2^4 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_2^4 = \frac{16}3 - \frac{20}3 = -\frac43

\displaystyle \int_4^6 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_4^6 = 12 - \frac{16}3 = \frac{20}3

and the overall integral would be

20/3 - (-4/3) + 20/3 = 44/3

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AlekseyPX

Answer:

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Step-by-step explanation:

Use your order of operations to solve this and you will understand how to do more like these in the future. Especially when your solving multi step equations. PEMDAS look it up and learn it by heart, it will help you so  much in the future


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