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stiv31 [10]
3 years ago
12

I need help please !!!

Mathematics
1 answer:
juin [17]3 years ago
6 0

Answer:

f = 12(s - 35).

Step-by-step explanation:

The number of miles per hour he was over the limit = s - 35.

So his fine f is:

f = 12(s - 35).

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Just divide it and it will get your answer
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I keep on getting the wrong answer
Anon25 [30]

1) Area = (b*h)/2 = (9*5)/2 = 45/2 = 22.5 (Letter A)

2) Area = b*h = 8*14 = 112 (Letter D)

3) Surface area of a prism is SA=2B+ph (B = area of the base, p = perimeter of the base, h = height)

B = 15 * 5 = 75 cm^2

p = 15 + 5 = 20 cm

SA = 2*75 + 20*7 = 150 + 140 = 290 (G)

4) V = (B*H*L)/2 = (15*7*5)/2  = 525/2 = 262.5 cm^3 (G)

5) V = 9^3 = 81 cm^3 worth of wrapping (A)

6) V = (B*H*L)/2 = (13*6*8)/2 = 312 cube feet (J)

It gave me ADGGAJ. I don't know if this is right, but I atleast tried to do something, right?

5 0
2 years ago
Read 2 more answers
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th
ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

H_0: \mu=500\\\\H_a:\mu< 500

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

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Answer:

i really dont knok but my guess is yes

Step-by-step explanation:

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