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Snezhnost [94]
3 years ago
6

Need help on Geometry right answers only

Mathematics
2 answers:
adell [148]3 years ago
8 0
The floor of the school has the shape of triangle.
So, the area of the floor is equal to the area of that triangle with base = 26 in, and height  = 33 in.
The area of triangle = 0.5 * base * height 
            = 0.5 * 26 * 33 = 429 in²

∴ The area of the floor = 429 in²
Sauron [17]3 years ago
8 0
The floor are is 429 in².

Since the floor has a shape of triangle, we need to use the formula:
Area-1/2base x height
Given:
 base = 26 in, and height  = 33 in.

SOlution:The area of triangle = 0.5 * base * height             = 0.5 * 26 * 33 = 429 in²
The area of the floor = 429 in²

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The height is modelled by the equation:

h(t)=-0.2t^2+2t

Therefore

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At the maximum height dh/dt = 0:

Hence,

\begin{gathered} -0.4t+2=0 \\ -0.4t=-2 \\ \text{ Dividing both sides by -0.4} \end{gathered}\begin{gathered} \frac{-0.4t}{-0.4}=\frac{-2}{-0.4} \\ t=5 \end{gathered}

Hence, the ball gets to the maximum height after 5s.

The maximum height is given by h(5):

h(5)=-0.2(5)^2+2(5)=5

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When the ball reaches the ground h(t) = 0:

\begin{gathered} -0.2t^2+2t=0 \\ \text{ Dividing both sides by -0.2, we have:} \\ t^2-10t=0 \\ Factorising\text{ the left hand side, we have} \\ t(t-10)=0 \\ \text{ Therefore,} \\ t=0,\text{ t=10} \end{gathered}

The ball reaches the ground in 10s

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