Choice A: 3 nights and one meal for $ 250
1 answer:
Let x be the price for each night and y be the price for each meal. Then, express the statements into mathematical equations:
Choice A: 3x + y = 250
Choice B: 3x + 6y = 330
Subtract both equations, the difference would be -5y = -80
-5y = -80
y = -80/-5
y = $16 per meal
3x + y = 250
3x + 16 = 250
3x = 250 - 16
3x = 234
x = 234/3
x = $78 per night
The answer is D.
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