For the difference to be positive, when both the minuend and the subtrahend are positive, the former must be greater than the latter.
Therefore
minuend = 2 ⇒ subtrahend = 1 ← 1 number
minuend = 3 ⇒ subtrahend = 1,2 ← 2 numbers
minuend = 4 ⇒ subtrahend = 1,2,3 ← 3 numbers
minuend = 5 ⇒ subtrahend = 1,2,3,4 ← 4 numbers
minuend = 6 ⇒ subtrahend = 1,2,3,4,5 ← 5 numbers
1+2+3+4+5=<u>15</u>
Answer:
W=7 and L=11
Step-by-step explanation:
We have two unknowns so we must create two equations.
First the problem states that length of a rectangle is 10 yd less than three times the width so: L= 3w-10
Next we are given the area so: L X W = 77
Then solve for the variable algebraically. It is just a system of equations.
3W^2 - 10W - 77 = 0
(3W + 11)(W - 7) = 0
W = -11/3 and/or W=7
Discard the negative solution as the width of the rectangle cannot be less then 0.
So W=7
Plug that into the first equation.
3(7)-10= 11 so L=11
Use properties of alternate angles then apply trigonometry
You should know the instructions and rules of all safety equipment
Answer:
Where the rectangle at?
Step-by-step explanation:
