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Veronika [31]
3 years ago
12

The figure below shows a shaded region and a nonshaded region. Angles in the figure that appear to be right angles are right ang

les.
What is the area, in square feet, of the shaded region?
Enter your answer in the box.

What is the area, in square feet, of the nonshaded region?
Enter your answer in the box.

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0
16 x 8 = 128 square feet (area of rectangle)

shaded:
8 x 2 = 16
10 x 1 = 10
1/2 (3)(10) = 15

total shaded area: 16+10+15 = 41 square feet
total non-shaded area = 128 - 41 = 87 square feet

answer

area of the shaded region = 41 square feet
area of the non - shaded region = 87 square feet
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<u>Answer:</u>

<u>For a:</u> The probability of getting a red or blue ball is 0.48

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<u>For c:</u> The probability of getting neither white or orange ball is 0.48

<u>Step-by-step explanation:</u>

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}     .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

  • <u>For a:</u>

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48

  • <u>For b:</u>

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81

  • <u>For c:</u>

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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ahrayia [7]

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