I need help with this question can anyone help plss. Its due very soon.
1 answer:
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Answer:
10, 12, 14, 16
Step-by-step explanation:
Given: Four consecutive even integers such that seven times the first exceeds their sum by 18.
Lets assume the first number be "x".
As it is even integers
∴ Second consecutive number will be
Third consecutive number will be
Fourth consecutive number will be
Now, as given seven times the first exceeds their sum by 18.
∴
solving the equation to find the number.
⇒
Opening parenthesis
⇒
subtracting both side by 4x
⇒
Dividing both side by 3
∴ x= 10.
Hence, subtituting the value x to find four consecutive even integers.
First number is 10
Second consecutive number will be = 12
Third consecutive number will be = 14
Fourth consecutive number will be = 16
∴ Four consecutive even integers are 10,12,14,16.
Here you go, hope it helps:)
