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Tatiana [17]
3 years ago
15

Write the expression as a square of a binomial: 9/25a^6b^2-a^4b^4+25/36a^2b^6

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

answer below,

<h2>Hope this helps :></h2><h2 /><h2>From Cambridge</h2><h2 /><h2>please give brainliest!</h2>

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Which one is correct? A,B,C, or D?
Paladinen [302]

Answer:

B

Step-by-step explanation:

3x-7 <-4

Firstly solve this.

+7 +7

3x<3

÷3 ÷3

x<1

And because the inequality symbol isn't "equal to", the circle isn't coloured in.

The line will go from 1 to behind 0

7 0
3 years ago
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What is the answer to 2 1/4 x 3 1/9
vlada-n [284]
2 1/4 times 3 1/9

Make the fractions into decimals

So now it’s 2.25 times 3.11...

Multiply that to get 6.99 but since the 3.11... is a repeated sequence you would round it to 7, which is your answer!
3 0
3 years ago
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Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x/6x^2 +
timama [110]

Looks like your function is

f(x)=\dfrac x{6x^2+1}

Rewrite it as

f(x)=\dfrac x{1-(-6x^2)}

Recall that for |x|, we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

If we replace x with -6x^2, we get

f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}

By the ratio test, the series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2

Solving for x gives the interval of convergence,

|x|^2

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.

3 0
3 years ago
Write the expression as a product of two factors.<br> 2* 1 + (1+7) + (762)
Arlecino [84]

Answer:

put answer in link

alekscgi/x/Isl.exe

Step-by-step explanation:

3 0
3 years ago
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!!Plz urgent help!!
Firdavs [7]

Answer:

890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(AB)(BC)

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

(13)² = 5² + BC²

169 = 25 + BC²

BC² = 144

BC = 12

Area of the triangular base = \frac{1}{2}(5)(12)

                                             = 30 cm²

Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

                                                   = 540 cm³

Volume of one spherical bead = \frac{4}{3}\pi r^{3}

                                                   = \frac{4}{3}\pi (0.525)^{3}

                                                   = 0.606 cm³

Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

n ≈ 890

Therefore, 890 beads can be fitted in the triangular prism.

3 0
3 years ago
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