In this case we know the three sides of the triangle, then this is a SSS triangle (Side Side Side). To solve this case, first we must use the Law of Cosines, applied to the opposite side to the angle we want to find.
We want to find angle W, and its opposite side is XV, then we apply the Law of Cosines to the side XV:
XV^2=XW^2+WV^2-2(XW)(WV)cos W
Replacing the known values:
116^2=96^2+89^2-2(96)(89)cos W
Solving for W
13,456=9,216+7,921-17,088 cos W
13,456=17,137-17,088 cos W
13,456-17,137=17,137-17,088 cos W-17,137
-3,681=-17,088 cos W
(-3,681)/(-17,088)=(-17,088 cos W)/(-17,088)
0.215414326=cos W
cos W = 0.215414326
Solving for W:
W= cos^(-1) 0.215414326
Using the calculator:
W=77.56016397°
Rounded to one decimal place:
W=77.6°
Answer: Third option 77.6°
<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50
</em></u></h3><h3><u><em>
2 lunches = $5.00 (2.50x2)
</em></u></h3><h3><u><em>
3 lunches =$7.50
</em></u></h3><h3><u><em>
4 lunches =$10.00
</em></u></h3><h3><u><em>
5 lunches= $12.50
</em></u></h3><h3><u><em>
Just add $2.50</em></u></h3>
125/12 would be your equivalent improper fraction
These quantities are related linearly with slope
3/2. without knowing the answer choices I can only give you examples of equations that fit
y-2=3/2(x-2). or y=3/2(x) -1
etc
Answer:
Both angles have a measure of 134degrees, y = 27degrees.
Step-by-step explanation:
As per what is given in the problem:
There are 2 parallel lines, both are intersected by a transversal.
Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.
The is meanse that:
3y + 53 = 7y - 55
Solve using inverse operations:
3y + 53 = 7y - 55
+55 +55
3y + 108 = 7y
-3y -3y
108 = 4y
/4 /4
27 = y
Now, substitute back in to find the value of the angle:
3y + 53
y = 27
3 ( 27 ) + 53
81 + 53
= 134
Since the angles are alternate exterior, they are congruent, hence both angles have a measure of 134degrees.
