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timofeeve [1]
3 years ago
15

The rate constant for this first‑order reaction is 0.470 s − 1 0.470 s−1 at 400 ∘ C. 400 ∘C. A ⟶ products A⟶products How long, i

n seconds, would it take for the concentration of A A to decrease from 0.920 M 0.920 M to 0.380 M?
Chemistry
1 answer:
azamat3 years ago
4 0

Answer : The time taken by the reaction is, 1.88 s

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.470s^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant  = 0.920 M

a - x = amount left after process = 0.380 M

Now put all the given values in above equation, we get

t=\frac{2.303}{0.470}\log\frac{0.920}{0.380}

t=1.88s

Therefore, the time taken by the reaction is, 1.88 s

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