Answer:
Below:
Explanation:
The Contact process If the temperature is increased, the equilibrium position moves in the direction of the endothermic reaction. This means it moves to the left in the Contact process. ... However, the rate of reaction is low at low temperatures. So, as in the Haber process, a compromise temperature of 450 °C is chosen.
Habar Process...
The Haber process, also called the Haber–Bosch process, is an artificial nitrogen fixation process and is the main industrial procedure for the production of ammonia today. It is named after its inventors, the German chemists Fritz Haber and Carl Bosch, who developed it in the first decade of the 20th century.
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The structure for this question is attached. I think the correct answer would be the fourth option. The common name of the structure would be ethyl isobutyl ketone. Other name would be 2-methyl-3-pentanone. It has a chemical formula of C7H14O or (CH3)2CHCH2C(O)CH2CH3. It is classified as an aliphatic ketone and is used as a solvent and a reagent in laboratory experiments. It is a VOC or volatile organic compound. This compound can also be found at times in normal human biofluids and in feces for about 25% of the population. At normal conditions, it exists as a solid compound.
Based on their position in the periodic table, fluorine is expected to have the greatest tendency to attract a shared pair of electrons.
The ability of elements to attract shared electrons in a bond is called electronegativity.
Electronegativity is a periodic trend that decreases down the group and increases across the period. This implies that, as we move across the period, the magnitude of electronegativity increases.
Based on this, we can see that fluorine in group 17 will have the greatest electronegativity since the electronegativity of noble gases is zero.
Learn more: brainly.com/question/2060520
The correct answer is elements in family 7 have similar properties because elements in the same group or family have the same number of valence electrons.
Answer:
Explanation:
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In this case, since the temperature and pressure are related via a directly proportional relationship, via the Gay-Lussac's law we can write:
Thus, since the initial temperature in kelvins is 294.15 K and the final temperature in kelvins is 364.15 K, we can compute the final pressure as shown below:
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