Answer:
See explanation
Explanation:
The electrolysis of nickel(II) iodide yields nickel solid and iodine gas.
In the oxidation half equation;
2I^-(aq)-------> I2(g) + 2e
In the reduction half equation;
Ni^2+(aq) + 2e -----> Ni(s)
These are the half equations of the process;
The overall equation is;
Ni^2+(aq) + 2I^-(aq)-------> NiI2
Answer:
It is given in the question that molarity of the sulphuric acid is 2M, the volume of the sulphuric acid is 20 mL, the volume of the solution is 1`L.
Answer: B
Explanation:i dont the explaniation but my dad is an expert in science so he told me the answer
Answer:
Option D is correct = 58 g
Explanation:
Data Given:
mass of LiOH = 120 g
Mass of Li3N= ?
Solution:
To solve this problem we have to look at the reaction
Reaction:
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol 3 mol
Convert moles to mass
Molar mass of LiOH = 24 g/mol
Molar mass of Li₃N = 35 g/mol
So,
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol (35 g/mol) 3 mol (24 g/mol)
35 g 72 g
So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of LiOH
For this apply unity formula
35 g of Li₃N ≅ 72 g of LiOH
X of Li₃N ≅ 120 g of LiOH
By Doing cross multiplication
Mass of Li₃N = 35 g x 120 g / 72 g
mass of Li₃N = 58 g
120 g of LiOH will produce from 58 g of Li₃N
So,
Option D is correct = 58 g
Answer: -
¹⁰B
Explanation: -
For ⁹Be,
The atomic number is 4.
The Mass number is 9.
The number of neutrons = mass number - atomic number
= 9 - 4 = 5
For ⁹B,
The atomic number is 5.
The Mass number is 9.
The number of neutrons = mass number - atomic number
= 9-5 = 4
For ¹⁰B,
The atomic number is 5.
The Mass number is 10.
The number of neutrons = mass number - atomic number
= 10-5 = 5
For ¹⁰Be,
TThe atomic number is 4.
The Mass number is 10.
The number of neutrons = mass number - atomic number
= 10-4 = 6
For ¹²C,
The atomic number is 6.
The Mass number is 12.
The number of neutrons = mass number - atomic number
= 12-6 = 6
