How many atoms are in 1.75 mol CHCL3
2 answers:
1 mol = 6.022 x 10²³ atoms
In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.
So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃
But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃
1 mol=6.022 * 10²³ (atoms or molecules) 1.75 moles of (CHCl3) we have: 1.75 moles*(6.022 10²³ molecules)=1.05385 10²⁴ molecules. a molecule of CHCl₃ have, 1 atom of C, 1 atom of H, and 3 atoms of Cl, therefore a molecule of CHCl3 have 1atom+1 atom +3 atom=5 atoms. Therefore: 1 molecule (CHCl₃)--------------------------------5 atoms 1.058385 10²⁴ molecules (CHCl₃)------------- x x=(1.058385 10²⁴ molecules* 5 atoms) / 1 molecule≈5.26925 *10²⁴ atoms.solution: ≈5.269 10²⁴ atoms.
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