Answer:
Taking into account the definition of average atomic mass and isotopes of an element, the information that you need is the masses of its isotopes and their percent abundances.
Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.
But in the nucleus of each element it is also possible to find neutrons, whose number can vary. The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus.
The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.
The atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.
The weighted average means that not all isotopes have the same percentage.
In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.
Explanation:
 
        
             
        
        
        
Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,


   
Compound's mass,
= 0.4647 g
Let the compound's formula will be:

Combustion's general equation will be:
⇒  
On putting the estimated values, we get
⇒  
⇒  
⇒  
⇒                     
Now,
x : y : z = 
            = 
            = 
            = 
So that the empirical formula seems to be "C₃H₆O₂".
 
        
             
        
        
        
Answer:
the answer is I'm pretty that it's 
Explanation:
Ur Wellcome 
 
        
             
        
        
        
Answer:
The  of a substrate will be "10 μM".
 of a substrate will be "10 μM".
Explanation:
The given values are:

![[Substract] = 40 \ \mu M](https://tex.z-dn.net/?f=%5BSubstract%5D%20%3D%2040%20%5C%20%5Cmu%20M)

Reaction velocity, 
As we know,
⇒  ![Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}](https://tex.z-dn.net/?f=Vo%3D%5Cfrac%7BK_%7Bcat%7D%5BE_%7Bt%7D%5D%5BS%5D%7D%7BK_%7Bm%7D%2B%5BS%5D%7D)
On putting the estimated values, we get
⇒  
⇒  
⇒  
On subtracting "40" from both sides, we get
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⇒  