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Dimas [21]
3 years ago
14

How many atoms are in 1.75 mol CHCL3

Chemistry
2 answers:
vaieri [72.5K]3 years ago
6 0

1 mol = 6.022 x 10²³ atoms

In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.

So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃

But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃

Alex Ar [27]3 years ago
5 0
1 mol=6.022 * 10²³ (atoms or molecules)
1.75 moles of (CHCl3) we have: 1.75 moles*(6.022 10²³ molecules)=1.05385  10²⁴ molecules.

a molecule of CHCl₃ have, 1 atom of C, 1 atom of H, and 3 atoms of Cl, therefore a molecule of CHCl3 have 1atom+1 atom +3 atom=5 atoms.
Therefore:

1 molecule (CHCl₃)--------------------------------5 atoms
1.058385 10²⁴ molecules (CHCl₃)-------------    x
x=(1.058385  10²⁴ molecules* 5 atoms) / 1 molecule≈5.26925  *10²⁴ atoms.

solution: ≈5.269  10²⁴ atoms.

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