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Dimas [21]
3 years ago
14

How many atoms are in 1.75 mol CHCL3

Chemistry
2 answers:
vaieri [72.5K]3 years ago
6 0

1 mol = 6.022 x 10²³ atoms

In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.

So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃

But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃

Alex Ar [27]3 years ago
5 0
1 mol=6.022 * 10²³ (atoms or molecules)
1.75 moles of (CHCl3) we have: 1.75 moles*(6.022 10²³ molecules)=1.05385  10²⁴ molecules.

a molecule of CHCl₃ have, 1 atom of C, 1 atom of H, and 3 atoms of Cl, therefore a molecule of CHCl3 have 1atom+1 atom +3 atom=5 atoms.
Therefore:

1 molecule (CHCl₃)--------------------------------5 atoms
1.058385 10²⁴ molecules (CHCl₃)-------------    x
x=(1.058385  10²⁴ molecules* 5 atoms) / 1 molecule≈5.26925  *10²⁴ atoms.

solution: ≈5.269  10²⁴ atoms.

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Answer:

Taking into account the definition of average atomic mass and isotopes of an element, the information that you need is the masses of its isotopes and their percent abundances.

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.

But in the nucleus of each element it is also possible to find neutrons, whose number can vary. The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.

The atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.

The weighted average means that not all isotopes have the same percentage.

In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

Explanation:

7 0
3 years ago
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of
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Answer:

The essence including its given problem is outlined in the following segment on the context..

Explanation:

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x = 0.01962

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= 0.4647 g

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On putting the estimated values, we get

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⇒  12\times 0.01962+1\times 0.03922+16\times z=0.4647

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Now,

x : y : z = 0.01962:0.03922:0.01187

           = \frac{0.01962}{0.0118}:\frac{0.03922}{0.0188}:\frac{0.0188}{0.0188}

           = 1.6:3.3:1.0

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3 years ago
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