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Tom [10]
4 years ago
10

Least common multiple of 78,90, and 140

Computers and Technology
2 answers:
Nastasia [14]4 years ago
6 0
The answer is 16380. List all the multiple of 78, 90, and 140, then find the least common multiple.
Daniel [21]4 years ago
5 0
The least common multiple (LCM) of 78, 90, and 140 is: 16,380

78 × 210 = 16,380
90 × 182 = 16,380
140 × 117 = 16,380
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Write a program that: Takes the list lotsOfNumbers and uses a loop to find the sum of all of the odd numbers in the list (hint:
Alika [10]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;

int main()//defining main method

{

int x[]={2,3,4,6,7,8,9,1,11,12};//defining 1-D array and assign value

int i,sum=0;//defining integer variable

for(i=0;i<10;i++)//defining loop for count value

{

   if(x[i]%2==1)//defining if block to check odd value

   {

       sum=sum+x[i];//add value in sum variable

   }

}

cout<<sum;//print sum

return 0;

}

Output:

31

Explanation:

In the above-given program, an integer array "x" is declared that holds some integer values, and in the next line two integer variable "i and sum" is defined which is used to calculate the value.

In the next line, a for loop is declared, that counts all array value, and it uses the if block to check the odd value and add all the value into the sum variable.

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3 years ago
Which of the following indicates the main benefit of having a larger hard drive on a computer
dem82 [27]
I would say the primary Beni fit is more space for storage , but also it does effect the speed eventually. If your hard drive is almost full, everything will be slower
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Turn-outs are features of roadways that are to be employed by
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3 0
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You can use ___________ to add dynamic features to a webpage such as search box that completes your search text automatically.
jonny [76]

Answer:

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Explanation:

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JavaScript allows users to enter the value and provide the result at the same time and very fast.

JavaScript can be used online or offline too.

JavaScript provided much functionality such as when a customer searches anything, it completes the search automatically.

5 0
3 years ago
Write a program that repeatedly accepts as input a string of ACGT triples and produces a list of the triples and the correspondi
Andre45 [30]

Answer:

Explanation:

The following code is written in Python. I created a dictionary with all the possible gene combinations and their corresponding amino acids. The user then enters a string. The string is split into triples and checked against the dictionary. If a value exists the gene and amino acid is printed, otherwise an "Invalid Sequence" error is printed for that triple. The program has been tested and the output can be seen in the attached image below.

def printAminoAcids():

   data = {

       'TTT': 'Phe', 'TCT': 'Ser', 'TGT': 'Cys', 'TAT': 'Tyr',

       'TTC': 'Phe', 'TCC': 'Ser', 'TGC': 'Cys', 'TAC': 'Tyr',

       'TTG': 'Leu', 'TCG': 'Ser', 'TGG': 'Trp', 'TAG': '***',

       'TTA': 'Leu', 'TCA': 'Ser', 'TGA': '***', 'TAA': '***',

       'CTT': 'Leu', 'CCT': 'Pro', 'CGT': 'Arg', 'CAT': 'His',

       'CTC': 'Leu', 'CCC': 'Pro', 'CGC': 'Arg', 'CAC': 'His',

       'CTG': 'Leu', 'CCG': 'Pro', 'CGG': 'Arg', 'CAG': 'Gln',

       'CTA': 'Leu', 'CCA': 'Pro', 'CGA': 'Arg', 'CAA': 'Gln',

       'GTT': 'Val', 'GCT': 'Ala', 'GGT': 'Gly', 'GAT': 'Asp',

       'GTC': 'Val', 'GCC': 'Ala', 'GGC': 'Gly', 'GAC': 'Asp',

       'GTG': 'Val', 'GCG': 'Ala', 'GGG': 'Gly', 'GAG': 'Glu',

       'GTA': 'Val', 'GCA': 'Ala', 'GGA': 'Gly', 'GAA': 'Glu',

       'ATT': 'Ile', 'ACT': 'Thr', 'AGT': 'Ser', 'AAT': 'Asn',

       'ATC': 'Ile', 'ACC': 'Thr', 'AGC': 'Ser', 'AAC': 'Asn',

       'ATG': 'Met', 'ACG': 'Thr', 'AGG': 'Arg', 'AAG': 'Lys',

       'ATA': 'Ile', 'ACA': 'Thr', 'AGA': 'Arg', 'AAA': 'Lys'

   }

   string = input("Enter Sequence or just click Enter to quit: ")

   sequence_list = []

   count = 0

   gene = ""

   for x in range(len(string)):

       if count < 3:

           gene += string[x]

           count += 1

       else:

           sequence_list.append(gene)

           gene = ""

           gene += string[x]

           count = 1

   sequence_list.append(gene)

   for gene in sequence_list:

       if gene.upper() in data:

           print(str(gene.upper()) + ": " + str(data[gene.upper()]))

       else:

           print(str(gene.upper()) + ": invalid sequence")

printAminoAcids()

5 0
3 years ago
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