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kirza4 [7]
3 years ago
12

A mountain climber ascends a mountain to its peak. The peak is 14,090 ft above sea level. The climber then descends 490 ft to me

et a fellow climber. Find the climber’s elevation above sea level after meeting the other climber. 9,190 ft 13,600 ft 14,580 ft –13,600 ft
Mathematics
1 answer:
lana66690 [7]3 years ago
7 0
The value of asked for is obtained by subtracting the distance traveled downward by the climber from the peak elevation. This is shown below,
                                    d = 14,090 ft - 490 ft
The value is equal to 13600 ft. Thus, the climber is 13,600 ft from the ground. 
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sertanlavr [38]

Answer:

21 weeks.

Step-by-step explanation:

To start, you have to get the pounds lost per week.

12/3=4

4 pounds lost per week.

Next, find out how many weeks it takes by solving this equation,

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Therefore, it took 21 weeks to lose 84 pounds.

6 0
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In a bank account a paid out expense is called a debit and a deposit is called a credit. Would you use positive or negative inte
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Answer:

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Step-by-step explanation:

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A deposit is called as credit

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3 years ago
Find the product in simplest form 8/21 * 5/16
Rus_ich [418]

Just multiply across which is

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This is correct answer

I hope this answer helped you!!! Thank you!!!

5 0
3 years ago
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Three vertices of a rectangle have coordinates (3,4), (5,−4), and (−7,−7). Determine the fourth vertex of the rectangle and then
Ket [755]
The fourth vertex would be at point (-9,1).
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7 0
3 years ago
Slope of 1,-7 and -3-4​
3241004551 [841]

\large \mathfrak{Solution : }

Slope of the given line is :

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where ,

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4 0
3 years ago
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