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Illusion [34]
3 years ago
10

64 is what percent of 800? (Equation please added)

Mathematics
2 answers:
ra1l [238]3 years ago
6 0

Answer: STOP

Step-by-step explanation:

Deffense [45]3 years ago
4 0

Answer:

64 is 8% of 800

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What is the value of s?<br> S=
barxatty [35]

Answer:

s = 1

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 5 , then

sum = 180° × 3 = 540°

sum the interior angles and equate to 540

39s + 129 + 79 + 145 + 148 = 540 , that is

39s + 501 = 540 ( subtract 501 from both sides )

39s = 39 ( divide both sides by 39 )

s = 1

6 0
3 years ago
In the figure shown, line AB is parallel to line CD. What is the
timurjin [86]
Since AB is a straight line, and straight lines are 180 degrees, you can add the two 62 degree angles.

62+62=124

180-124=56

angle x is 56 degrees
3 0
3 years ago
A person on the top of a tall building looks through his binoculars at his friend that is 300 ft away from the building on the g
Gnesinka [82]
In this instance the distance will be the hypotenuse of a right angle triangle.
x = 300/sin30 = 600

They are 600 ft away from each other
4 0
3 years ago
Solve for z.<br><br> ln63=lnz+ln7<br><br> Enter your answer in the box.
Bumek [7]

Answer:

<em>z </em>= 9

Step-by-step explanation:

ln 63 = ln z + ln 7

We have the formula:

ln A + ln B = ln AB

So, ln 63 = ln 7<em>z</em>

7<em>z </em>= 63

Divide both sides by 7.

\frac{7z}{7}=\frac{63}{7}

<em>z</em> = 9

7 0
3 years ago
Read 2 more answers
Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 &amp; c, d are roots of x² - 20x + 2022 then the value of ac(a
Alja [10]
<h3><u>Correct Question :- </u></h3>

\sf\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0 \: and \:  \\  \sf \: c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0 \: then \:

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =

(a) 0

(b) 8000

(c) 8080

(d) 16000

\large\underline{\sf{Solution-}}

Given that

\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0}

We know

\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}

\rm \implies\:ab = \dfrac{ - 2020}{1}  =  - 2020

And

\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}

\rm \implies\:a + b = -  \dfrac{20}{1}  =  - 20

Also, given that

\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0}

\rm \implies\:c + d = -  \dfrac{( - 20)}{1}  =  20

and

\rm \implies\:cd = \dfrac{2020}{1}  = 2020

Now, Consider

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)

\sf \:  =  {ca}^{2} -  {ac}^{2} +  {da}^{2} -  {ad}^{2} +  {cb}^{2} -  {bc}^{2} +  {db}^{2} -  {bd}^{2}

\sf \:  =  {a}^{2}(c + d) +  {b}^{2}(c + d) -  {c}^{2}(a + b) -  {d}^{2}(a + b)

\sf \:  = (c + d)( {a}^{2} +  {b}^{2}) - (a + b)( {c}^{2} +  {d}^{2})

\sf \:  = 20( {a}^{2} +  {b}^{2}) + 20( {c}^{2} +  {d}^{2})

\sf \:  = 20\bigg[ {a}^{2} +  {b}^{2} + {c}^{2} +  {d}^{2}\bigg]

We know,

\boxed{\tt{  { \alpha }^{2}  +  { \beta }^{2}  =  {( \alpha   + \beta) }^{2}  - 2 \alpha  \beta  \: }}

So, using this, we get

\sf \:  = 20\bigg[ {(a + b)}^{2} - 2ab +  {(c + d)}^{2} - 2cd\bigg]

\sf \:  = 20\bigg[ {( - 20)}^{2} +  2(2020) +  {(20)}^{2} - 2(2020)\bigg]

\sf \:  = 20\bigg[ 400 + 400\bigg]

\sf \:  = 20\bigg[ 800\bigg]

\sf \:  = 16000

Hence,

\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}

<em>So, option (d) is correct.</em>

4 0
2 years ago
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