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3 years ago

64 is what percent of 800? (Equation please added)

Mathematics

2 answers:

ra1l [238]3 years ago

6 0

Answer: STOP

Step-by-step explanation:

Deffense [45]3 years ago

4 0

Answer:

64 is 8% of 800

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What is the value of s? S=

barxatty [35]

Answer:

s = 1

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 5 , then

sum = 180° × 3 = 540°

sum the interior angles and equate to 540

39s + 129 + 79 + 145 + 148 = 540 , that is

39s + 501 = 540 ( subtract 501 from both sides )

39s = 39 ( divide both sides by 39 )

s = 1

6 0

3 years ago

In the figure shown, line AB is parallel to line CD. What is the

timurjin [86]

Since AB is a straight line, and straight lines are 180 degrees, you can add the two 62 degree angles.

62+62=124

180-124=56

angle x is 56 degrees

3 0

3 years ago

A person on the top of a tall building looks through his binoculars at his friend that is 300 ft away from the building on the g

Gnesinka [82]

In this instance the distance will be the hypotenuse of a right angle triangle.
x = 300/sin30 = 600

They are 600 ft away from each other

4 0

3 years ago

Solve for z. ln63=lnz+ln7 Enter your answer in the box.

Bumek [7]

Answer:

z = 9

Step-by-step explanation:

ln 63 = ln z + ln 7

We have the formula:

ln A + ln B = ln AB

So, ln 63 = ln 7z

7z = 63

Divide both sides by 7.

$\frac{7z}{7}=\frac{63}{7}$

z = 9

7 0

3 years ago

Read 2 more answers

Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 & c, d are roots of x² - 20x + 2022 then the value of ac(a

Alja [10]

<h3>Correct Question :- </h3>

$\sf\:a,b \: are \: the \: roots \: of \: {x}^{2} + 20x - 2020 = 0 \: and \: \\ \sf \: c,d \: are \: the \: roots \: of \: {x}^{2} - 20x + 2020 = 0 \: then \:$

$\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =$

(a) 0

(b) 8000

(d) 16000

$\large\underline{\sf{Solution-}}$

Given that

$\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \: {x}^{2} + 20x - 2020 = 0}$

We know

$\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}$

$\rm \implies\:ab = \dfrac{ - 2020}{1} = - 2020$

And

$\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}$

$\rm \implies\:a + b = - \dfrac{20}{1} = - 20$

Also, given that

$\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \: {x}^{2} - 20x + 2020 = 0}$

$\rm \implies\:c + d = - \dfrac{( - 20)}{1} = 20$

and

$\rm \implies\:cd = \dfrac{2020}{1} = 2020$

Now, Consider

$\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)$

$\sf \: = {ca}^{2} - {ac}^{2} + {da}^{2} - {ad}^{2} + {cb}^{2} - {bc}^{2} + {db}^{2} - {bd}^{2}$

$\sf \: = {a}^{2}(c + d) + {b}^{2}(c + d) - {c}^{2}(a + b) - {d}^{2}(a + b)$

$\sf \: = (c + d)( {a}^{2} + {b}^{2}) - (a + b)( {c}^{2} + {d}^{2})$

$\sf \: = 20( {a}^{2} + {b}^{2}) + 20( {c}^{2} + {d}^{2})$

$\sf \: = 20\bigg[ {a}^{2} + {b}^{2} + {c}^{2} + {d}^{2}\bigg]$

We know,

$\boxed{\tt{ { \alpha }^{2} + { \beta }^{2} = {( \alpha + \beta) }^{2} - 2 \alpha \beta \: }}$

So, using this, we get

$\sf \: = 20\bigg[ {(a + b)}^{2} - 2ab + {(c + d)}^{2} - 2cd\bigg]$

$\sf \: = 20\bigg[ {( - 20)}^{2} + 2(2020) + {(20)}^{2} - 2(2020)\bigg]$

$\sf \: = 20\bigg[ 400 + 400\bigg]$

$\sf \: = 20\bigg[ 800\bigg]$

$\sf \: = 16000$

Hence,

$\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}$

So, option (d) is correct.

4 0

2 years ago