Three cards are selected from a standard deck of <span>52 </span><span>cards. Disregarding the order in which they are drawn, the possible outcomes are </span><span><span>(<span>52/3</span>)</span></span><span>. Out of these, how many include all cards of the same color (say red)? There are </span><span><span>(<span>13/3</span>)</span></span><span> ways in which you can get all 13 red cards.</span>
Answer:
(a)0.16
(b)0.588
(c)![[s_1$ s_2]=[0.75,$ 0.25]](https://tex.z-dn.net/?f=%5Bs_1%24%20s_2%5D%3D%5B0.75%2C%24%20%200.25%5D)
Step-by-step explanation:
The matrix below shows the transition probabilities of the state of the system.

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix
.
(a)


If the system is initially running, the probability of the system being down in the next hour of operation is the 
The probability of the system being down in the next hour of operation = 0.16
(b)After two(periods) hours, the transition matrix is:

Therefore, the probability that a system initially in the down-state is running
is 0.588.
(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.
Since we have two states, ![S=[s_1$ s_2]](https://tex.z-dn.net/?f=S%3D%5Bs_1%24%20%20s_2%5D)
![[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]](https://tex.z-dn.net/?f=%5Bs_1%24%20%20s_2%5D%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D0.90%260.10%5C%5C0.30%260.70%5Cend%7Barray%7D%5Cright%29%3D%5Bs_1%24%20%20s_2%5D)
Using a calculator to raise matrix P to large numbers, we find that the value of
approaches [0.75 0.25]:
Furthermore,
![[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]](https://tex.z-dn.net/?f=%5B0.75%24%20%200.25%5D%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D0.90%260.10%5C%5C0.30%260.70%5Cend%7Barray%7D%5Cright%29%3D%5B0.75%24%20%200.25%5D)
The steady-state probabilities of the system being in the running state and in the down-state is therefore:
![[s_1$ s_2]=[0.75$ 0.25]](https://tex.z-dn.net/?f=%5Bs_1%24%20s_2%5D%3D%5B0.75%24%20%200.25%5D)
Answer is choice C: If a line is drawn through point A and point X, then it will bisect line segment BC.
This line is the third missing median of the triangle. A median goes from one vertex to the midpoint of the opposite side. The midpoint cuts the segment in half. For example, median CD cuts segment AB in half (AD = DB). All three medians of a triangle meet at the same point: the centroid
The probability of hitting the third ring is the same as finding what percentage is the area of the third ring out of the total area of the board.
The area of the third ring = The total area of the board - The area of the second circle.
Refer to the diagram below
The diameter for the whole circle = 32 in
The radius = 16 in
The area of the whole circle = π(16)² = 256π
The diameter for the second circle = 22 in
The radius = 11 in
The area of the second circle = π(11)² = 121π
The area of the third ring = 256π - 121π = 135π
Area of the third ring as a percentage of the total area =

= 52.7%
The answer is C. 136.
I hope this helps.