Please help it’s geo!

Given: M(-4,-1), B(-5,-3) find the midpoint

Dmitry [639]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
M&({{ -4}}\quad ,&{{ -1}})\quad 
% (c,d)
B&({{ -5}}\quad ,&{{ -3}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -5}}-4}{2}\quad ,\quad \cfrac{-3-1}{2} \right)$

4 0

3 years ago

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Solve using any method. Choose the correct ordered pair.

lesya692 [45]

Answer:

C

Step-by-step explanation:

-2 + 7 = 5

7 0

3 years ago

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The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough

liberstina [14]

Answer:

a) $t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

$\bar X=1175$ represent the sample mean for the cubic feets of households

$\sigma=250$ represent the population standard deviation

$n=100$ sample size

$\mu_o =1425$ represent the value to verify

$\alpha=0.025$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1425$

Alternative hypothesis: $\mu < 1425$

Since we don't know the deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0

3 years ago

What is the value of x? 1/2(x-14)+11=1/2x-(x-4)

mylen [45]

The answer is x=0 hope this helps

6 0

3 years ago

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0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store

g100num [7]

This question is incomplete, the complete question is;

The Millennium Falcon is chased by the Imperial Forces. The ship is moving at a speed of 0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store for $20.00 plus 6.00% TAX. The cannon emits protons at a speed of 0.741 c with respect to the ship.

What is the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction? 0.911 ANS .

What is the velocity of the protons in the resting frame when the cannon is shot in the backward direction?

(Use positive sign for the forward direction, and negative for the backward direction.)

Answer:

A)

the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

B)

the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Step-by-step explanation:

Given that;

speed of ship u = 0.525C

speed of proton emission v = 0.741C

Now When Cannon is shot in Forward Direction

Relativistic speed S is Calculated as;

S = (u+v) / ((1 + (uv))/c²)

we substitute (0.525 + 0.741 )C / ((1 + (0.525 × 0.741) C)/c²)

the C² cancel each other

so we have

S = 1.266 / 1.389925

S = 0.9108 ≈ 0.911c

Therefore the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

When Cannon is shot in Backward Direction

Relativistic speed S is Calculated as;

S = ( u – v ) / ( 1 – uv / c ²)

S = (0.525 - 0.741) C / ((1 - (0.525 × 0.741) C)/c²)

the C² cancel each other

so S = -0.216 / 0.610975

S = -0.3535c

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Therefore the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

7 0

3 years ago