Question

What is the range of the function y =^3 Square root x+ 8?

Answer 1

Answer:

  all real numbers

Step-by-step explanation:

The range of any odd root function is all real numbers, cube root included.

  y = ∛(x+8)

is defined for all values of x. It may take on any value for y.

____

The horizontal scale of the graph is quite large so as to show the vertical extent keeps increasing. (The x-intercept is -8.)

Answer 2

Answer:

The range of the function is: -∞≤y≤∞.

Step-by-step explanation:

Consider the provided function

$y=\sqrt[3]{x+8}$

The range of the function is the set of all values which a function can produce or the set of y values which a function can produce after substitute the possible values of x.

The range of a cubic root function is all real numbers.

Now consider the provided function.

$y=\sqrt[3]{x+8}$

The above function can be written as:

$y=(x+8)^{\frac{1}{3}}$

Taking cube on both sides.

$y^3=x+8\\\\x=y^3-8$

The graph of the function is shown in figure 1:

For any value of x we can find different value of y.

Here, the cube root function can process negative values. Since, the function can produce any values, the range of the given function is  -∞≤y≤∞ .

Therefore, the range of the function is: -∞≤y≤∞.