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3 years ago

A laboratory experiment requires 2400 milligrams of sugar. How many kilograms of sugar does the experiment require?

Mathematics

1 answer:

telo118 [61]3 years ago

5 0

Answer:

0.0024

Step-by-step explanation:

1 killogram=1000000

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Which shows the expression x^2-1/x^2-x in simplest form

____ [38]

Answer:

$\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}$

Step-by-step explanation:

$\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}$

4 0

3 years ago

Read 2 more answers

What is the average rate of change for h(t) between t=0 and t=2

nordsb [41]

Part a: Option D 18 feet per second

Part b: increasing

Solution:

Height $h(t)=-16 t^{2}+50 t+3$

Part a: To find the average rate of change for h(t) between t = 0 and t = 2.

Substitute t = 0 in h(t).

$h(0)=-16 (0)^{2}+50 (0)+3$

h(0) = 3

Substitute t = 2 in h(t).

$h(2)=-16 (2)^{2}+50 (2)+3$

h(2) = 39

Average rate of change formula:

$$=\frac{h(b)-h(a)}{b-a}$

Here, a = 0 and b = 2.

$$=\frac{h(2)-h(0)}{2-0}$

$$=\frac{39-3}{2}$

$$=\frac{36}{2}$

= 18

Average rate of change = 18 feet per second

Option D is the correct answer.

Part b:

This means height of the ball is increasing for 0 < x < 2.

6 0

2 years ago

Look at the picture below for the question i need help with. I pretty sure you need to find the y-intercept...

daser333 [38]

Answer:

20.00

Explanation:

You can see that with every two coffees the amount is decreasing by 3.50 each time

The slope is -1.75 which is for every one coffee so this multiplied by 2 = 3.50

8 0

2 years ago

Brilliant question!!!!

avanturin [10]

Answer:

a) 21

b) 78.5 - 28.3 - 12.57 = 37.63

Step-by-step explanation:

For the triangle, you want to use the formula 1/2 base times height and then subtract 2 time 2. For the circle, the formula is pi times the radius squared. Then, subtract the other circles using the same formula. I hope this helps! Please mark me brainliest because I have been scammed many times. Please and thank you.

6 0

2 years ago

Read 2 more answers

In Canada in 1998 the estimated number of households that owned 2 or more vehicles was 3.939 x 10 6

WITCHER [35]

In Canada in 1998 the estimated number of households written in standard decimal notation is 3939000

<u>Solution:</u>

Given that in 1998 estimated number of households that owned 2 or more vehicles was $3.939 \times 10^{6}$

Need to represent the number $3.939 \times 10^{6}$ in standard decimal notation.

In this case we need to move the decimal point based on the power of 10.

In our case power of 10 = 6.

Let’s first take a number without $10^6$ and add six zeros on right.

So we get 3.939000000

Now multiplying above number by $10^6$ means moving the decimal after 6 numbers from the current position, that means

$3.939 \times 10^{6}=3939000.00$

That is 3939000 is required standard decimal notation of scientific notation number $3.939 \times 10^{6}$

5 0

3 years ago