Answer:
C.1/6
Step-by-step explanation:
Initially the box has four $1 and six $5 bills. The probability of selecting a $5 bill in the first trial would be given as;
(number of $5 bills) / (total number of bills)
= (6)/(4+6) = 3/5
If in the first attempt we actually pick a $5 bill, the number of $5 bills will reduce by one to 5. Now, the probability of picking a $5 bill in the second attempt will be given as;
(new number of $5 bills) / (new total number of bills)
= (5)/(4+5) = 5/9
The new number of $5 bills will now be; 6 - 2 = 4 since we have already picked 2 without replacing them.
Now, the probability of picking a $5 bill in the third attempt will be given as;
(new number of $5 bills) / (new total number of bills)
= (4)/(4+4) = 1/2
Since the three attempts are independent, the probability of picking all three $5 bills is;
3/5 * 5/9 * 1/2 = 1/6
Turn the question around.
If all the numbers were positive: 2.5, 1.6, 3 1/10, 1/10, and 0.5, which would be farthest to the right?
The fact is that the negative numbers are a reflection of the positive numbers.
Since 3 1/10 would be farthest to the right with positive numbers, -3 1/10 will be farthest to the left with the negative numbers.
Answer:
Population of Africa in 2003 is 22.5 million
population of Africa in 1950 is 1 million - 22.5 million /5
21.5million / 5
21500000/5
4300000
4.3 million people
