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joja [24]
3 years ago
15

Which term of the arithmetic sequence 1 , 6 , 11 , 16 , ... 1,6,11,16,... is 136?

Mathematics
1 answer:
UNO [17]3 years ago
7 0
The nth term = the first term +(n-1)d, d is the difference between two adjacent terms, in this case, d=5
136=1+5(n-1)
136=5n-4
5n=140
n=28

so the 28th term is 136
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