Answer:
You have to type in the Numbers to the boxes
Step-by-step explanation:
Box A = 18
Box B = 20
In the Middle is 5 and 6
In Box c- 10,15,11
Answer:
(9 - 4 x)/(x (2 x - 4))
Step-by-step explanation:
Simplify the following:
1/(2 x^2 - 4 x) - 2/x
Put each term in 1/(2 x^2 - 4 x) - 2/x over the common denominator x (2 x - 4): 1/(2 x^2 - 4 x) - 2/x = ((x (2 x - 4))/(2 x^2 - 4 x))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4)):
((x (2 x - 4))/(2 x^2 - 4 x))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))
A common factor of 2 x - 4 and 2 x^2 - 4 x is 2 x - 4, so (x (2 x - 4))/(2 x^2 - 4 x) = (x (2 x - 4))/(x (2 x - 4)):
((x (2 x - 4))/(x (2 x - 4)))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))
(x (2 x - 4))/(x (2 x - 4)) = 1:
1/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))
1/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4)) = (1 - 2 (2 x - 4))/(x (2 x - 4)):
(1 - 2 (2 x - 4))/(x (2 x - 4))
-2 (2 x - 4) = 8 - 4 x:
(8 - 4 x + 1)/(x (2 x - 4))
Add like terms. 1 + 8 = 9:
Answer: (9 - 4 x)/(x (2 x - 4))
Answer:
No probllem linked
Step-by-step explanation:
Answer:
Dang someone come help him
Step-by-step explanation:
25 students got 2 chaperones
so 1 will get 2/25
and thus 8 will get 2/25×8 = 0.64 chaperone
but is it possible?? No chaperone can not be in decimal so at least 1 is required !!
