Answer:
Step-by-step explanation:
Question 2
As far as I can see, you got it right. The general transformation for 90 ccw is
(x,y) ===> (-y, x)
What that means is for the x you put in -y changing the sign to the opposite and for the y you put in x and this time you leave the sign alone . The transformation is shown in the left hand diagram.
The two tables are shown below.
Original
The transformed table is
- (-4,1)
- (-2,1)
- (-2,3)
- (-5,3)
- (-4,1) This is just to let the program know to close the figure For some reason this did not have lines and if I delete it and put the lines in, I won't be able to upload the new diagram.
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Four
This one transforms from (x,y) to (-x,-y) which means where you see an x, you put a - x and where you see a y, you put a minus y. It is the middle frame.
Original
- (-4,3)
- (0,3)
- (-2,0)
- (-4,3) Here again, this is just to close the figure.
The transformed figure in red I think is
- (4,-3)
- (0,-3
- (2,0)
- (4,-3) And this closes the figure as well.
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Six
The diagram is on the right
Reflection about the y axis. Here the transformation is (x,y) ====> (-x,y) notice the ys don't change.
There is no closure.
Reflection
In order to answer the question we need the lengths to do the math.
Answer: If i'm correct i think the subsets of b are
={0},{1},{2},{0,1},{1,2} ,{2,0},{0,1,2},{phye}
Step-by-step explanation:
Answer:
f(2) =30
Step-by-step explanation:
f(1)=15
f(n)=f(n-1)*n
Put in n=2
f(2)=f(2-1)*2
= f(1) *2
= 15*2
=30
The 95% confidence interval of voters not favoring the incumbent is (0.0706, 0.1294).
Sample size, n=400
Sample proportion, p = 40 / 400
= 0.1
We use normal approximation, for this, we check that both np and n(1-p) >5.
Since n*p = 40 > 5 and n*(1-p) = 360 > 5, we can take binomial random variable as normally distributed, with mean = p = 0.1 and standard deviation = root( p * (1-p) /n )
= 0.015
For constructing Confidence interval,
Margin of Error (ME) = z x SD = 0.0294
95% confidence interval is given by Sample Mean +/- (Margin of Error)
0.1 +/- 0.0294 = (0.0706 , 0.1294)
Learn more about Margin of Error here brainly.com/question/15691460
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