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liberstina [14]
4 years ago
10

Find the missing variable for the following direct variation k= -2; (x, -8)

Mathematics
1 answer:
jonny [76]4 years ago
3 0

Answer:

4

Explanation:

y ¤ x...where ¤ represents the Greek alpha sign...

y = k • x

-8 = -2 • x

-8/-2 = x

4 = x

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Carlos ran 7 miles in 57 3/4 minutes. How fast did he run each mile?
Kay [80]
How fast did he run each mile, that is to say how fast did he run 1 mile.

We can simply find the time it took him to run 1 mile.

He ran 7 miles in 57  3/4 minutes = 57.75 minutes.

In 1 mile he would run = 57.75/7 minutes = 8.25 minutes.

He ran 1 mile, that is each mile in 8.25 minutes.

I hope this helped.
4 0
4 years ago
Emily is entering a bicycle race for charity. Her mother pledges $0.10 for every 0.25 mile she bikes. If Emily bikes 8 miles, ho
Arlecino [84]

Answer:

0.10 for 1/4 of a mile so 8 would be 32 times more. Which would be .1 x 32 or $3.20

Step-by-step explanation:

Plz mark brainliest :3

8 0
3 years ago
9 (x-y)^2-9 (x+y)(x-y)
bazaltina [42]
<h2>Answer</h2>

This answer is 18y • (y - 1)

<h2>Explanation</h2>

Step by step solution:

Equation at the end of step 1:

9 (x - y) ^2 - 9 (x^{2} - y^{2})

Equation at the end of step 2:

9 (x^2 + y^2 - 2xy) - 9 (x^2 - y^2)

Equation at the end of step 3:

9x^2 + 9y^2 - 18xy - 9x^2 + 9y^2

Equation at the end of step 4:

After performing basic +, - operation we get:

18y^2 - 18xy

Answer is: 18y. (y – x)


3 0
3 years ago
What is 0.1 10 times as much
Gnom [1K]
So 0.1 really means 1/10 of 1 so  10 times of 1/10 is 10/10 or 1
8 0
3 years ago
Read 2 more answers
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
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