The value of the radius of T is 28 units
<h3>
How to determine the value of the radius of T</h3>
From the question, we understand that:
Segment AB is tangent to T at B
This means that
<ABT = 90
So, we have a right triangle
Let the radius of the triangle be r
By the Pythagoras theorem, we have
AT^2 = AB^2 + VT^2
This gives
(25 + r)^2 = 45^2 + r^2
Open the bracket
625 + 50r + r^2 = 2025 + r^2
Subtract r^2 from both sides of the equation
625 + 50r = 2025
Subtract 625 from both sides of the equation
50r = 1400
Divide both sides by 50
r = 28
Hence, the value of the radius of T is 28 units
Read more about tangent at:
brainly.com/question/17040970
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Answer:
y - 5 = 
(x - 1)
Step-by-step explanation:
Note that 
= 
Differentiate using the power rule
(a
) = na
Given
y = x
= x. 
= 
, then
=
When x = 1
= . 1 =
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = and (a, b) = (1, 5), thus
y - 5 = (x - 1) ← equation of tangent
5 I think I'm not surreeeeee
Applying parallel line postulate twice
36degree=3x degree +2y degree
126 degrees=12 x degree + 2y degree
So, the two equations are:
3x + 2y = 36
and
12x + 2y = 126
Eliminate x to solve for y
-(3x + 2y)= -(36)
-3x - 2y = -36
Combine the equations
(-3x - 2y)+ (12x + 2y) = (-36) + (126)
-3x -2y + 12x + 2y = -36 + 126
9x = 90
x = 10
Plug value of x back into to the equations to solve for y
3(10) + 2y = 36
30 + 2y = 36
2y =6
y = 3
Optional
Plug x into the other equation to check for error
12(10) +2y = 126
120 + 2y =126
2y = 6
y = 3
