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loris [4]
3 years ago
11

What expression is equivalent to 3x + 14 + 3x + 10?

Mathematics
1 answer:
Archy [21]3 years ago
4 0
What expression is equivalent to 3x + 14 + 3x + 10.

The answer is 6x+ 24
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Prove that Tan x + Cos x = 1 /Sin x .Cos x​
Anit [1.1K]

Answer:

tanx + cotx =  \frac{1}{sinxcosx}

Step-by-step explanation:

<u><em>Explanation</em></u>

Take R.H.S   = \frac{1}{sinxcosx}

            =      \frac{sin^{2}x+cos^{2}x  }{sinxcosx}

          =      \frac{sin^{2}x }{sinx cosx} + \frac{cos^{2} x}{sinxcosx}

        = \frac{sinx}{cosx} + \frac{cosx}{sinx}

        = tanx + cotx

tanx + cotx =  \frac{1}{sinxcosx}

             

5 0
3 years ago
Given a population with a mean of muμequals=100100 and a variance of sigma squaredσ2equals=3636​, the central limit theorem appl
lakkis [162]

Answer:

a) \bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)

\mu_{\bar X}=100 \sigma^2_{\bar X}=1

b) P(\bar X >101)=1-P(\bar X

c) P(\bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".  

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

Let X the random variable that represent the variable of interest on this case, and for this case we know the distribution for X is given by:  

X \sim N(\mu=100,\sigma=6)  

And let \bar X represent the sample mean, by the central limit theorem, the distribution for the sample mean is given by:  

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})  

a. What are the mean and variance of the sampling distribution for the sample​ means?

\bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)

\mu_{\bar X}=100 \sigma^2_{\bar X}=1.2^2=1.44

b. What is the probability that x overbarxgreater than>101

First we can to find the z score for the value of 101. And in order to do this we need to apply the formula for the z score given by:  

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

If we apply this formula to our probability we got this:  

z=\frac{101-100}{\frac{6}{\sqrt{25}}}=0.833  

And we want to find this probability:

P(\bar X >101)=1-P(\bar X

On this last step we use the complement rule.  

c. What is the probability that x bar 98less than

First we can to find the z score for the value of 98.

z=\frac{98-100}{\frac{6}{\sqrt{25}}}=-1.67  

And we want to find this probability:

P(\bar X

5 0
3 years ago
Point E is the midpoint of ab and point f is the midpoint of CD
Lorico [155]

AB is bisected by CD (TRUE). This is True because E is the midpoint between A and B and CD passes through E

CD is bisected by AB (FALSE) CD is bisected by point F and not AB

AE = 1/2 * AB (TRUE) since E is the midpoint of AB , E divides AB into two equal halves

EF = 1/2 * ED (FALSE) The true statement would have been CF = 1/2* CD

FD = EB (FALSE) sinc we do not know if CD and AB are of the same lengths

CE + EF = ED (TRUE) since F is the midpoint the sum of CE and EF is equal to ED



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