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nlexa [21]
3 years ago
14

A 12-oz can of soda pop costs eighty-nine cents. A 2.00 L bottle of the same variety of soda pop costs $2.29. How many times mor

e expensive it is to buy the 12-oz can of pop compared to buying it in a 2.00 L bottle? (1.00 L = 1.057 quart and 1 quart contains 32 oz)
Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0

Answer: It's 2.2 times more expensive to buy the 12-oz can of pop compared to buying it in a 2.00 L bottle

Step-by-step explanation:

You know that:

1.00\ L = 1.057\ quarts

1.00\ quart=32\ oz

Then, you can make the conversion from liters to quarts:

(2.00\ L)(\frac{1.057\ quarts}{1.00\ L})=2.114\ quarts

Now, you need to make the conversion from quarts to ounces:

(2.114\ quarts)(\frac{32\ 0z}{1.00\ quart})=67.648\ oz

You know that a 12-oz can of soda pop costs 89 cents (which is $0.89). Then, the cost per ounce is:

\frac{\$0.89}{12}=\$0.074

 And a 2.00 L bottle (67.648 oz) of the same variety of soda pop costs $2.29. The cost per ounce is:

\frac{\$2.29}{67.648}=\$0.033

Finally, you must divide $0.074 by $$0.033:

\frac{\$0.074}\$0.033}=2.2

Therefore, It's 2.2 times more expensive to buy the 12-oz can of pop compared to buying it in a 2.00 L bottle.

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Answer:

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30 (15 minutes after the first 15 minutes) - 19

\frac{27 - 46}{15 - 0} = -h (27 - Tenv)

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\frac{19 - 27}{15 - 0} = -h (19 - Tenv)\\\frac{-8}{15} = -h (19 - Tenv)\\\frac{8}{15} = h (19 - Tenv)\\\frac{8}{15} = \frac{19}{15(27 - Tenv)} (19 - Tenv)\\8(27 - Tenv) = 19 (19 - Tenv)\\216 - 8 Tenv = 361 - 19 Tenv\\19 Tenv - 8 Tenv = 361 - 216\\11 Tenv = 145 \\Tenv = 145/ 11\\Tenv = 13. 18

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