<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.
The answer is: 45 * 10 ⁻¹¹ .
___________________________________________
Explanation:
____________________________________________
Given: (9 * 10⁻⁵) * (5 *10 ⁻⁶) ; Simplify.
____________________________________________
(9 * 10⁻⁵) * (5 *10⁻⁶) =
9 * 5 * 10⁻⁵ * 10⁻⁶ =
(9 * 5) * 10⁻⁵ * 10⁻⁶
45 * 10⁻⁵ * 10⁻⁶ ;
______________________________________
Note the following property of exponents:
xᵃ * xᵇ = x⁽ᵃ⁺ᵇ⁾ ;
As such, 10⁻⁵ * 10⁻⁶ = 10⁽⁻⁵ ⁺ ⁻⁶) = 10 ⁻¹¹ ;
______________________________________
So; 45 * 10⁻⁵ * 10⁻⁶
= 45 * 10⁻¹¹ .
______________________________________
Answer:
f(n) = 8.5n
Step-by-step explanation:
$8.50 * n = Gross
Sq of 196 is 14 then x2 = 28 then 25= 5
Factors of 4 : 1,2,4
factors of 10 : 1,2,5,10
