Answer:
a. $121.07
b. $60.9
C. $20.03
Step-by-step explanation:
From the equation given
Y=181.7-20.21x
Where y is in dollars and X is in years
a. To find the resale price after 3years we have, we substitute x=3 into the given equation.
We have
y=181.7-20.21(3)
y=181.7-60.63
y=121.07
The resale price after 3years is $121.07
b. To find the resale price after 6years we have, we substitute x=6 into the given equation.
We have
y=181.7-20.21(6)
y=181.7-120.72
y=60.98
The resale price after 3years is $60.98
C. To find the average decrease per year, we have
[(x=3)-(x=6)]/3
=(121.07-60.98)/3
$20.03
Hence the average annual decrease is $20.03
Answer:
d) All of the above
Step-by-step explanation:
A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).
In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.
In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.
This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.
The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.
Let's say we are comparing the means of k population. The degree of freedom would be = k - 1
The correct option here is (d).
All of the above
Answer:
a) Эx ∈ R ⊇ x³ = 2
b) ∀x ∈ R, x² ≥ 0
c) Эx ∈ R ⊇ x³ = x
d) ∀x ∈ R, x ≤ x²
Step-by-step explanation:
Given the data in the question;
let us first go through some symbols and their possible meanings;
Э ⇒ there exists
∀ ⇒ for all
∈ ⇒ belongs to or set membership or element of the set
⊇ ⇒ such that
now;
a) There is a number whose cube is equal to 2
let x represent the number; so
Эx ∈ R ⊇ x³ = 2
b) The square of every number is at least 0
x² ≥ 0, ∀x ∈ R
∀x ∈ R, x² ≥ 0
c) There is a number that is equal to its square
Эx ∈ R ⊇ x³ = x
d) Every number is less than or equal to its square.
x ≤ x², ∀x ∈ R
∀x ∈ R, x ≤ x²
Answer:
The answer is A. piecewise
Step-by-step explanation:
