Mation about which osi layers of connected cisco devices can be verified with the show cdp neighbors comm
1 answer:
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Answer:
Explanation:
The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.
import java.io.*;
import java.util.*;
class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
int answer = 0;
while (true) {
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
answer = in.nextInt();
if (answer > 0) {
months[n-1] = answer;
break;
}
}
}
}
public void getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is " + total);
}
public void getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is " + average);
}
public void getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amount of rainfall was " + largest +
" inches in month " + (largeind + 1));
}
public void getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amount of rainfall was " + smallest +
" inches in month " + (smallind + 1));
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
r.getTotal();
r.getSmallest();
r.getLargest();
r.getAverage();
}
}
Answer:
The complete Matlab code along with step by step explanation is provided below.
Matlab Code:
function Req=ParallelR(Number)
Number=input('Please enter the number of resistors: ');
if Number>10 | Number<=0
disp('Invalid input')
return
end
R=0;
for i=1:Number
r=input('Please enter the value of resistor: ');
R=R+1/r;
end
Req=1/R;
end
Explanation:
Parallel resistance is given by
First we get the input from the user for how many parallel resistors he want to calculate the resistance.
Then we check whether the user has entered correct number of resistors or not that is from 1 to 10 inclusive.
Then we run a for loop to get the resistance values of individual resistors.
Then we calculated the parallel resistance and keep on adding the resistance for N number of resistors.
Output:
Test 1:
Please enter the number of resistors: 3
Please enter the value of resistor: 10
Please enter the value of resistor: 20
Please enter the value of resistor: 30
ans = 60/11
Test 2:
Please enter the number of resistors: 11
Invalid input
Test 3:
Please enter the number of resistors: 0
Invalid input
