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kumpel [21]
3 years ago
10

? Which console was the first to use CD-ROM storage? PlayStation Atari Jaguar PlayStation 3 Xbox 360

Computers and Technology
1 answer:
kaheart [24]3 years ago
7 0

that is incorrect! Playstation is the correct answer

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1D Array Assignment Outcome: Student will demonstrate the ability to use a one-dimensional array. Student will demonstrate the a
sukhopar [10]

Answer:

Program to this question as follows:

program:

import java.util.*; //import package for user input

public class Main  //defining class  

{

public static void main(String[] as)//defining main function

{//defining integer array

int [] num = new int[113];  

boolean find_in = false; //defining boolean variable

int [] counts = new int[101];//defining integer array

int y, tem = 0, counter = 0,in=0,x,find; //defining integer variable

Scanner ox= new Scanner(System.in); //creating Scanner class Object

while(counter <= 112) //loop to check condition

{

num[counter++] = generateRandomNumber(); //using array to hold random function value.  

}

System.out.println("The array:"); //message

for(x = 0; x < 112; x++) // loop to count the value

{

if(x != 0 && x % 9 == 0) // if block to chek value

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// sort in ascending order

Arrays.sort(num); //using sort method

System.out.print("\n\nThe array in sorted order:"); // print value

for( x = 0; x < num.length; x++) // loop uses if block to check value is divisiable by 9  

{

if(x % 9 == 0) //check condition  

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// search for a number

System.out.print("\n\nEnter a number to search: "); // print message

find= ox.nextInt(); // input number by user

for(x= 0;x< num.length;x++) //loop to count values

{

if(num[x] == find) //check value

{

find_in = true; //change value

in= x;

break; //using break keyword

}

}

if(find_in)  //find value

System.out.println(find + " is found at index " + in); // print location

else

System.out.println("Not found"); //message

// display count of each numbers

System.out.println("Count of each numbers:"); //message

for(y = 1; y< num.length; y++) // loop to store element in counts array  

{

tem = num[y]; //hold value

counts[tem]++; //increment value

}

for(x = 1; x< counts.length; x++) //loop to print value

{

System.out.println(x + ": " + counts[x]); // print value

}

// average of the numbers in the array

for(x = 0; x < num.length; x++) // loop to calculate sum and average

{

sum += num[x]; //calculate sum

}

avg = (sum / 100); // calculate avg

System.out.println("\nThe average of the numbers in the array: " + avg);

// highest number in the array

int high= num[0]; //find number

for(x= 0;x < num.length;x++)

{

if(num[x] > high)

high = num[x]; //hold value of highest Number

}

System.out.println("\nThe highest number is: " + high); //print value

int low = num[0]; // defining variable for lowest number

for(x= 0; x < num.length - 1; x++) // loop to calculate lowest number

{

if(num[x] < low) //condition for lowest number

low = num[x]; //hold lowest number

}

System.out.println("\nThe lowest number is: " + low); //print value

}

public static int generateRandomNumber() //defining function  

{

Random ra = new Random(); //creating Random function Object

return (ra.nextInt(100)+ 1); //input and return value

}

}

Output:

the output of the given code is display in image

Explanation:

In the above program, an array is declared that uses a random function to input the number, in the next step the sort function is used, that sorted all array elements, in the next step the scanner class is used, that input the number form the user ends and pass search in the sorted array.

  • After searching the average of array elements is calculated. In this array we calculate the highest and lowest number of the array to print all the values the print method is used.
  • At the last, the rand method is used that generates the random number for the array and passes into a num array that prints the values.

7 0
3 years ago
give one word • pressure exerted by a stationary liquid _______. • force in a direction perpendicular to a given surface area __
mel-nik [20]

Answer:

1. Hydrostatic pressure.

2. Pressure.

3. Equilibrium forces.

Explanation:

1. <u>Hydrostatic pressure</u>: pressure exerted by a stationary liquid. It is simply the pressure in a liquid such as water at a specific depth.

Mathematically, hydrostatic pressure is given by the formula;

H.P = rho * g * d

Where:

  • H.P is the hydrostatic pressure of a liquid.
  • rho represents the density of a liquid.
  • g is the acceleration due to gravity.
  • d is the depth (height) of a liquid.

2. <u>Pressure</u>: it is the force in a direction perpendicular to a given surface area. Thus, it's typically measured in Newton per meters (N/m²).

Mathematically, pressure is given by the formula;

Pressure = \frac {Force}{area}

3. <u>Equilibrium forces</u>: a pair of forces whose resultant is zero. It is also referred to as balanced forces because the resultant of all the pair of forces acting on a body or system is at equilibrium (balanced).

6 0
3 years ago
An open intersection is one that
alekssr [168]

 open intersection is one without traffic control signs or signals. When you enter one, you must yield the right-of-way if: A vehicle is already in the intersection. You enter or cross a state highway from a secondary road. hope this helped


4 0
3 years ago
Read 2 more answers
WILL MARK BRAIN LIST!
Tcecarenko [31]

Answer:

try D not sure

Explanation:

sorry if wrong happy if right!!!!!!

6 0
3 years ago
Read 2 more answers
A graphic design student is putting the finishing touches on her PowerPoint presentation for her speech. She is carefully analyz
elixir [45]

Answer:

Balance

Explanation:

Maintaining balance entails making sure things are in the right place, in the right proportion and maintaining a stable look and stand.

Maintaining a balance on a power point presentation entails that one considers these; ths one should carefully analyse how the different images go together and ensure that the positioning of elements within the images helps to make the individuals point and is pleasing to view.

This can be tasking but worth every effort put in to achieve such, because it will make your presentation to be easier to explain and better understood.

7 0
3 years ago
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