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3 years ago

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Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

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1/9
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There's your answer.

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Someone help me please

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Answer:

Step-by-step explanation:

Plug in the standard deviation formula. This is new to me but it took some research.. Hope it helps

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2 years ago

Find the fifth term of the binomial expansion. (x2+y5) ^8

OlgaM077 [116]

Answer:

The fifth term of the binomial expansion

$T_{5} = 70 x^{8} y^{20}$

Step-by-step explanation:

Step:1

Given that the binomial expansion

( x² + y⁵ )⁸

we know that

$T_{r+1} = n_{C_{r} } a^{r} x^{n-r}$ ...(i)

Step:2

put r = 4

$T_{4+1} = 8_{c_{4} } (x^{2} )^{4} (y^{5} )^{8-4}$

$T_{5} = 70 x^{8} y^{20}$

Final answer:-

The fifth term of the binomial expansion

$T_{5} = 70 x^{8} y^{20}$

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What is the equation of the line of symmetry for the parabola represented by the equation y=−2(x−3)^2+4 ? Enter your answer as t

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$\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ y=-2(x-\stackrel{h}{3})^2+\stackrel{k}{4}\qquad\qquad \stackrel{vertex}{(\underline{3},4)}\qquad \qquad \stackrel{\textit{axis of symmetry}}{x=\underline{3}}$

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2 years ago