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3 years ago

Which of the following numbers is different

Mathematics

1 answer:

nadezda [96]3 years ago

5 0

Answer:

(D) 1/4%

hope that helps uh..☺

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A pet shop had 8 identical fish tanks in the shape of rectangular prisms. The width and height of each tank was (x - 7) inches a

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The area of rectangular base of each tank

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3 years ago

Please help 21 points!!!!!

harina [27]

Step-by-step explanation:

The measure of angle y is 62°.

I solve this by

We know: Measures of interior angles in a triangle add up to 180°.

Therefore we have the equation:

60° + 58° + y = 180°

118° + y = 180° <em>subtract 118° from both sides</em>

118° - 118° + y = 180° - 118°

y = 62°

The measure of angle x is 122°.

I solve this by

Angles 58° and x are supplementary angles.

Supplementary angles add up to 180°.

Therefore we have the equation:

x + 58° = 180° <em>subtract 58° from both sides</em>

x + 58° - 58° = 180° - 58°

x = 122°

8 0

3 years ago

The quotient of (x4 + 5x3 – 3x – 15) and a polynomial is (x3 – 3). What is the polynomial?

solmaris [256]

Answer:

Dividend

$=x^4 + 5 x^3 - 3 x - 15$

Divisor

$=x^3-3$

The rule of division of polynomial which is same as division of real numbers states that

Dividend = Divisor × Quotient + Remainder

The division process is shown below.

Quotient = x+5

Remainder =0

3 0

3 years ago

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Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)

timama [110]

<h3>Answer: c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

$f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\$

With a = -5 and b = 4, we have

$f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\$

So,

$f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\$

Use algebra to solve for c

$-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\$

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3 years ago

Melanie asked 15 random seventh-grade students how many soccer games they attended this school year. The number of games attende

Burka [1]

Answer:

Step-by-step ex: 13:15

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3 years ago

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