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4 years ago

Water flows at a steady rate from a tap.

Mathematics

2 answers:

vredina [299]4 years ago

5 0

Answer:

5000

Step-by-step explanation:

The question is related to conversion of units between litres and $cm^{3}$ .

1 litre is equivalent to 1 cubic decimetre.

1 decimetre = 10 centimetre

Converting cubic decimetre to cubic centimetre:

1 cubic decimetre = (10 * 10 * 10) cubic centimetre

Or, 1 cubic decimetre = 1000 cubic centimetre

In other words, 1 litre = 1000 cubic centimetre

Therefore, 5 litre = 5* 1000 cubic centimetre = 5000 cm³

n200080 [17]4 years ago

3 0

Answer: 5,000cm³
Well, 1 mL (milliliter) is equivalent to 1 cubic centimeter (cm³). There is 1,000 mL in a liter, so there are 5,000 mL in 5 liters and therefore 5 liters equals 5,000 cm³.

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5 0

3 years ago

What is the solution to the inequality |2n+5|>1

tekilochka [14]

Answer:

ANSWER

n < - 3 \: or \: n > - 2n<−3orn>−2

EXPLANATION

The given inequality is,

|2n + 5| \: > \: 1∣2n+5∣>1

By the definition of absolute value,

- (2n + 5) \: > \: 1 \: or \: (2n + 5) \: > \: 1−(2n+5)>1or(2n+5)>1

We divide through by negative 1, in the first part of the inequality and reverse the sign to get,

2n + 5 \: < \: - 1 \: or \: (2n + 5) \: > \: 12n+5<−1or(2n+5)>1

We simplify now to get,

2n \: < \: - 1 - 5 \: or \: 2n \: > \: 1 - 52n<−1−5or2n>1−5

2n \: < \: - 6 \: or \: 2n \: > \: - 42n<−6or2n>−4

Divide through by 2 to obtain,

n \: < \: - 3 \: or \: n \: > \: - 2n<−3orn>−2

7 0

3 years ago

Somebody help me with this ASAP!!!! IT'S DUE TOMORROW!! Btw the question is: The figures in each pair have the same perimeter. F

N76 [4]

So if the perimeters are equal then you know
Rectangle Triangle
x + x + x + 4 + x + 4 = x + x + 9 + x + 5

which becomes

4x + 8 = 3x + 14

now you can solve the equation for x, then find the perimeters

8 0

4 years ago

A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of

Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

Hours of TV per week (X): 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of hours of TV watched per week = $\frac{\sum X}{n}$ = 9.65

s = sample standard deviation = $\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }$ = 4.61

n = sample of people = 20

$\mu$ = true average number of hours of TV watched per week

Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 80% confidence interval for the true average, $\mu$ is ;

P(-1.33 < $t_1_9$ < 1.33) = 0.80 {As the critical value of t at 19 degrees of

freedom are -1.33 & 1.33 with P = 10%}

P(-1.33 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.33) = 0.80

P( $-1.33 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

P( $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $9.65-1.33 \times {\frac{4.61}{\sqrt{20} } }$ , $9.65+1.33 \times {\frac{4.61}{\sqrt{20} } }$ ]

= [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0

3 years ago

What is the molarity of a solution

Vika [28.1K]

Answer:

0.670. M

Step-by-step explanation:

Molarity can be expressed like this:

molarity = number of moles /volume (L)

We know the volume, which is 2.37 L , but we need to find the number of moles. We can do this by dividing 67.3 g by the molar mass of L i C l :

number of moles = mass of sample /molar mass

number of moles = 67.3 g /(6.94 + 35.45) g/mol = 67.3 g /42.39 g/mol

number of moles = 1.59 mol

molarity = 1.59 mol /2.37 L = 0.670. M

7 0

3 years ago