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tigry1 [53]
3 years ago
11

Divide by long division: (3d^2+2d-29)/(d+3)

Mathematics
1 answer:
Vesna [10]3 years ago
7 0
The dividend of the given expression above is,
     3d² + 2d - 29

and its divisor is equal to d+3. The steps in the long division are written below.

1. First, divide the first term of the dividend (3d²) by first term of the divisor (d). This gives us 3d. 

2. Next, multiply the answer, 3d, by the divisor (d+3). This gives us 3d² + 9d.

3. Then, subtract the answer, 3d² + 9d from the dividend, 3d²+2d-29. This gives us,

                      -7d - 29

4. Next, divide the first term of -7d by the first term of the divisor, d. This gives us the answer of -7.

5. Next, multiply the answer, -7, by the divisor, d+3. This gives us -7d-29

6. Then, subtract the answer in step 5 from the answer in step 3. This gives us,
     -7d-29 - (-7d-39) = 0

7. Combining the answer in steps 1 and 4 for the final answer will give us the answer of
          3d-7

<em>Answer: 3d-7</em>


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PLEASE HELP?? If arc AB = 70°, how many degrees are in ∠ ADB? A) 35° B) 50° C) 70° D) 110°
defon

Answer:

∠ADB=35°

Step-by-step explanation:

Given arc AB = 70°.

we have to find the angle ∠ADB

Here, Angle subtended by arc AB at O is ∠AOB = 70°

By the theorem,

The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.

∴ ∠AOB=2(∠ADB)

⇒ \angle ADB=\frac{1}{2}\angle AOB=\frac{1}{2}70^{\circ}= 35^{\circ}

hence, angle subtended at the circumference is 35°




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Step-by-step explanation:

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