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tigry1 [53]
3 years ago
11

Divide by long division: (3d^2+2d-29)/(d+3)

Mathematics
1 answer:
Vesna [10]3 years ago
7 0
The dividend of the given expression above is,
     3d² + 2d - 29

and its divisor is equal to d+3. The steps in the long division are written below.

1. First, divide the first term of the dividend (3d²) by first term of the divisor (d). This gives us 3d. 

2. Next, multiply the answer, 3d, by the divisor (d+3). This gives us 3d² + 9d.

3. Then, subtract the answer, 3d² + 9d from the dividend, 3d²+2d-29. This gives us,

                      -7d - 29

4. Next, divide the first term of -7d by the first term of the divisor, d. This gives us the answer of -7.

5. Next, multiply the answer, -7, by the divisor, d+3. This gives us -7d-29

6. Then, subtract the answer in step 5 from the answer in step 3. This gives us,
     -7d-29 - (-7d-39) = 0

7. Combining the answer in steps 1 and 4 for the final answer will give us the answer of
          3d-7

<em>Answer: 3d-7</em>


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Can anyone help me solve this
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Answer:

The answer to your question is a = 40, b = 5/8

Step-by-step explanation:

Data

  ab = 25

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Process

1.- Use the law log of a quotient

               log₄ a/b = 3

2.- Convert the log to an exponent

                   a/b = 4³

                   a/b = 64      Equation l

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3.- Solve equation l for a

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4.- Substitute in equation ll

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-Simplify

                    64b² = 25

-Solve for b

                         b² = 25/64

                         b = 5/8

5.- Substitute the value of b to find a

                     a = 64(5/8)

-Simplification

                     a = 40                        

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Answer:

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