Answer:
y-5 = -6(x+3) OR y = -6x-13
Step-by-step explanation:
Let's use slope-intercept form to solve this problem.
Slope intercept form is the following:
y-y1 = m(x-x1)
x1 and y1 are given by the point in the problem.
x1 = -3, y1 = 5.
m is given by the equation in the problem. Lines that are parallel have the same slope. Thus,
m = -6.
If we plug these values into the equation for slope intercept form, we get the following:
y-5 = -6(x-(-3)) which becomes y-5 = -6(x+3)
This is an acceptable answer to the problem. However, point-slope form is also a way it can be written.
y-5 = -6x-18
y = -6x-13
Answer: 749,250
Step-by-step explanation:
700,000 + 40,000= 740,000.
9,000+200+50= 9,250.
740,000 + 9,250 = 740,250.
Answer: A
Step-by-step explanation:
Answer:
C. 44 °
Step-by-step explanation:
Angles on a straight line add up to 180 degrees.
180 - 88 = 92
Angles in a triangle add up to 180 degrees.
y + y + 92 = 180
y + y = 88
2y = 88
y = 88/2
y = 44
Answer:
1-i and -1+i
Step-by-step explanation:
We are to find the square roots of 
. First, convert from Cartesian to polar form:
Next, use the formula ![\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5Bn%5D%7Br%7D%5Cbiggr%5B%5Ccis%5Cbiggr%28%5Cfrac%7B%5Ctheta%2B2%5Cpi%20k%7D%7Bn%7D%5Cbiggr%29%5Cbiggr%5D)
where 
to find the square roots:
<u>When k=1</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%281%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)
![\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B3%5Cpi%7D%7B4%7D%2B%5Cpi%5Cbiggr%29%5Cbiggr%5D)
<u>When k=0</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%280%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)
Thus, the square roots of -2i are 1-i and -1+i
