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Ksivusya [100]
3 years ago
8

Xavier, Yessie, and Zorro each choose a different favorite positive fraction. Each fraction is in simplest form. Yessie's fracti

on is the reciprocal of Xavier's. Zorro multiplies his favorite fraction by Xavier's and finds a product of 12/35. Zorro then multiplies his favorite fraction by Yessie's fraction and finds a product of 15/7. What is each person's favorite fraction?
Mathematics
1 answer:
ad-work [718]3 years ago
8 0
Let Xavier's favourite fraction be a/b, Yessie's favourite fraction = b/a and Zorro's favourite fraction = c/d,

c/d x a/b = 12/35 . . . . . . . . (1)
c/d x b/a = 15/7 . . . . . . . . (2)

(1) x (2) = c/d x a/b x c/d x b/a = 12/35 x 15/7
 c^2 / d^2 = 36/49
c^2 = 36
c = 6
d^2 = 49
d = 7

Xaviers favourite fraction = 12/35 / 6/7 = 2/5
Yessies favourite fraction = 5/2
Zorro favourite fraction = 6/7
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Answer:

The shortest side of the triangle is 3 inches.

Step-by-step explanation:

Given:

The ratio of the measure of the sides of the triangle is 1/6: 1/3: 1/4.

The perimeter = 13.5 inches.

Now, to find the shortest side.

<em>Let the one side be \frac{1}{6}x</em>

<em>And the second side be  \frac{1}{3}x.</em>

<em>And the third side be  \frac{1}{4}x.</em>

According to question:

\frac{1}{6}x+\frac{1}{3}x+\frac{1}{4}x=13.5

⇒\frac{x}{6}+\frac{x}{3}+\frac{x}{4}=13.5

Adding all the variables by taking common denominator we get:

⇒\frac{9x}{12}=13.5

<em>Multiplying both sides by 12 we get</em>:

⇒9x=162

<em>Dividing both sides by 9 we get</em>:

⇒x=18

Thus, <em>the sides of the triangle are</em>:

<u>1/6×18=3 inches.</u>

<u>1/3×18=6 inches.</u>

<u>1/4×18=9/2=4.5 inches</u>.

Therefore, the shortest side of the triangle is 3 inches.

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409,821,735,673 value of the digit 4 in this number.
gulaghasi [49]
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What is 8/16 in lowest term
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1/2

Step-by-step explanation:

if you find the LCD of the numbers, you will find that it is 8. Then, you divide both of them by 8 and you get 1/2

Hope this helped a bit :)

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The farmer was packing oranges for shipping. He had 5,342 oranges to pack and each box holds 25 oranges. How many full boxes of
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213 or 213.68 or 214

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In the figure above, the vertices of square
Olin [163]

(C) 6 + 3√3

<u>Explanation:</u>

Area of the square = 3

a X a = 3

a² = 3

a = √3

Therefore, QR, RS, SP, PQ = √3

ΔBAC ≅ ΔBQR

Therefore,

\frac{BQ}{BA} = \frac{QR}{AC}

\frac{BQ}{BA} = \frac{\sqrt{3} }{BA}

In ΔBAC, BA = AC = BC because the triangle is equilateral

So,

BQ = √3

So, BQ, QR, BR = √3 (equilateral triangle)

Let AP and SC be a

So, AQ and RC will be 2a

In ΔAPQ,

(AP)² + (QP)² = (AQ)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

Similarly, in ΔRSC

(SC)² + (RS)² = (RC)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

So, AP and SC = 1

and AQ and RC = 2 X 1 = 2

Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR

Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3

Perimeter = 6 + 3√3

Therefore, the perimeter of the triangle is 6 + 3√3

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