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shusha [124]
3 years ago
14

Please select all that apply

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

ceg and cfg

Step-by-step explanation:

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Two containers designed to hold water are side by side, both in the shape of a
quester [9]

Answer:

hope you don't mind but im using this for points

5 0
2 years ago
What are the intercepts of f(x)=(3x-4)(7x+2)
torisob [31]

Answer:

1. (-0,286; 0), (1,333; 0)

2. (0; -8)

5 0
3 years ago
2. When Joey dives off a diving board, the equation of his pathway can be modeled by h = -16- + 15 + 12.
Sergeu [11.5K]

Answer:

a) The maximum height is approx 15.5 unit.

b) The time it will take for Joey to reach the water is 1.45 hour.

Step-by-step explanation:

Given : When Joey dives off a diving board, the equation of his pathway can be modeled by h(t)= -16t^2+15t + 12

To find : a) Find Joey's maximum height.

b) Find the time it will take for Joey to reach the water.

Solution :

Modeled  h(t)= -16t^2+15t + 12 ....(1)

a) To find maximum height

Derivate (1) w.r.t. t,

h'= -32t+15

For critical point put h'=0,

-32t+15=0

t=\frac{15}{32}

t=0.46875

Derivate again w.r.t. t,

h''= -32

It is maximum at t=0.46875.

Substitute t in equation (1),

h(0.46875)= -16(0.46875)^2+15(0.46875)+12

h(0.46875)= -3.515625+7.03125+12

h(0.46875)= 15.515625

The maximum height is approx 15.5 unit.

b) To find the time it will take for Joey to reach the water.

Put h=0 in equation (1),

-16t^2+15t + 12=0

Apply quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=-16 , b=15, c=12

t=\frac{-15\pm\sqrt{(15)^2-4(-16)(12)}}{2(-16)}

t=\frac{-15\pm\sqrt{225+768}}{-32}

t=\frac{-15\pm\sqrt{993}}{-32}

t=\frac{-15+\sqrt{993}}{-32},\frac{-15-\sqrt{993}}{-32}

t=−0.515,1.453

Reject negative value.

The time is t=1.45.

The time it will take for Joey to reach the water is 1.45 hour.

5 0
3 years ago
What is the value of the following expression?<br> 2 x {6 + [12 + (3 + 1)]} - 1
dedylja [7]

Answer:

43

Step-by-step explanation:

2*(18+3+1)-1

2*(21+1)-1

2*22-1

44-1

A=43

8 0
3 years ago
Ivan knows two sides of a triangle are 16 meters and 6 meters. What two values must the third side be between
IrinaVladis [17]

Answer:

Third side lies between 10 & 22.

Step-by-step explanation:

Any side of triangle is greater than difference of two sides. Sum of two sides of triangle is always greater than third side.

So, letting third size be = x

Difference of two sides < Third side x < Sum of two sides

Difference of two sides = 16 - 6 = 10 , Sum of two sides = 16 + 6 = 22

Hence, 10 < Third side x < 22

5 0
3 years ago
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